QuestionHow does the equilibrium system adjust when $\mathrm{H}_{2} \mathrm{~S}$ gas is removed? A, B, C, or D?

Studdy Solution
As the reaction shifts to the right, more $\mathrm{NH}_{4} \mathrm{HS}$ will be consumed to produce more $\mathrm{NH}_{3}$ and $\mathrm{H}_{2} \mathrm{~}$. This means the concentration of $\mathrm{NH}_{3}$ will increase.
The correct answer is C. The reaction shifts to the right (products) and the concentration of $\mathrm{NH}_{3}$ increases.