QuestionIf possible, find $A+B, A-B, 3 A$, and $3 A-4 B$. (If not possible, enter IMPOSSIBLE in any cell of the matrix.) $$A=\left[\begin{array}{rrr} 7 & 0 & 3 \\ -4 & -2 & 0 \end{array}\right], \quad B=\left[\begin{array}{ll} 9 & -1 \\ 1 & -4 \end{array}\right]$$ (a) $A+B$ (b) $A-B$ (c) $3 A$ (d) $3 A-4 B$

Studdy Solution
To calculate $3A - 4B$, both matrices must have the same dimensions. Since $A$ is $2 \times 3$ and $B$ is $2 \times 2$, they do not have the same dimensions, and $3A - 4B$ is not possible.
Result for $3A - 4B$: IMPOSSIBLE
The results are: (a) $A + B$: IMPOSSIBLE (b) $A - B$: IMPOSSIBLE (c) $3A$: $\begin{bmatrix} 21 & 0 & 9 \\ -12 & -6 & 0 \end{bmatrix}$ (d) $3A - 4B$: IMPOSSIBLE