QuestionFind $\delta$ for $f(x)=x^{\frac{2}{3}}$ as $x \to 1$ with $\varepsilon=0.001$ such that $|f(x)-L|<\varepsilon$.

Studdy Solution
The larger of these differences is $.003$, so we set $\delta = .003$.
Therefore, if $|x-|<.003$, then $|f(x)-|<.001$.