Math / CalculusQuestionQuestion Evaluate the indefinite integral given below. ∫(−6x6−4xx2−4e6x)dx\int\left(\frac{-6 x^{6}-4 x}{x^{2}}-4 e^{6 x}\right) d x∫(x2−6x6−4x−4e6x)dxProvide your answer below: ∫(−4e6x+−6x6−4xx2)dx=\int\left(-4 e^{6 x}+\frac{-6 x^{6}-4 x}{x^{2}}\right) d x=∫(−4e6x+x2−6x6−4x)dx= □\square□Studdy Solution∫(−4e6x+−6x6−4xx2)dx=−65x5−4ln∣x∣−23e6x+C \int\left(-4 e^{6 x}+\frac{-6 x^{6}-4 x}{x^{2}}\right) d x = -\frac{6}{5}x^5 - 4\ln|x| - \frac{2}{3}e^{6x} + C ∫(−4e6x+x2−6x6−4x)dx=−56x5−4ln∣x∣−32e6x+CView Full Solution - FreeWas this helpful?