Math  /  Algebra

QuestionRewrite each equation as requested. (a) Rewrite as a logarithmic equation. 20=12^{0}=1 (b) Rewrite as an exponential equation. log5125=2\log _{5} \frac{1}{25}=-2 (a) log=\log _{\square} \square= \square (b) =\square= \square

Studdy Solution
Rewrite the logarithmic equation log5125=2\log_{5} \frac{1}{25} = -2 as an exponential equation.
The exponential form is:
52=1255^{-2} = \frac{1}{25}
This matches the format =\square = \square.
The rewritten equations are: (a) log21=0\log_{2} 1 = 0 (b) 52=1255^{-2} = \frac{1}{25}

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