Math  /  Data & Statistics

QuestionThe table shows the probability distribution for a discrete random variable XX. a. Complete the table by finding the missing values of xP(x)x \cdot P(x). Then compute the mean of the probability distribution. \begin{tabular}{|r|r|r|} \hlinexx & P(x)P(x) & xP(x)x \cdot P(x) \\ \hline 3 & 0.19 & \\ \hline 4 & 0.2 & 0.8 \\ \hline 5 & 0.37 & \\ \hline 6 & 0.24 & 1.44 \\ \hline \end{tabular} μX=4.66\mu_{X}=4.66

Studdy Solution
Compute the sum:
μX=4.66 \mu_X = 4.66
The completed table and mean are:
\begin{tabular}{|r|r|r|} \hline x & P(x) & x \cdot P(x) \\ \hline 3 & 0.19 & 0.57 \\ \hline 4 & 0.2 & 0.8 \\ \hline 5 & 0.37 & 1.85 \\ \hline 6 & 0.24 & 1.44 \\ \hline \end{tabular}
The mean of the probability distribution is:
μX=4.66 \mu_X = 4.66

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