Question$\int_{1}^{2} \frac{1}{x^{5}} d x$

Studdy Solution
Subtract the evaluated values to find the definite integral:
$-\frac{1}{64} - \left(-\frac{1}{4}\right) = -\frac{1}{64} + \frac{1}{4}$
Convert $\frac{1}{4}$ to a fraction with a denominator of 64:
$\frac{1}{4} = \frac{16}{64}$
Now perform the subtraction:
$-\frac{1}{64} + \frac{16}{64} = \frac{15}{64}$
The value of the definite integral is:
$\boxed{\frac{15}{64}}$