Math  /  Calculus

Questionyx=xyy=??\begin{array}{l}y^{x}=x^{y} \\ y^{\prime}=? ?\end{array}

Studdy Solution
نقوم بحل المعادلة بالنسبة لـ yy':
y=yxln(y)xyln(x)y' = \frac{\frac{y}{x} - \ln(y)}{\frac{x}{y} - \ln(x)}
هذه هي المشتقة المطلوبة yy' بالنسبة لـ xx.

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