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Archive
/
Math
Equation
Problem 11601
Express
8
1
2
x
81^{2 x}
8
1
2
x
and
2
7
3
y
27^{3 y}
2
7
3
y
as powers of 3, then find the ratio
x
:
y
x:y
x
:
y
if they are equal.
See Solution
Problem 11602
Given
2
x
=
16
2^{x}=16
2
x
=
16
and
2
y
=
64
2^{y}=64
2
y
=
64
, find: (a)
2
x
+
y
2^{x+y}
2
x
+
y
, (b)
2
x
−
y
2^{x-y}
2
x
−
y
, (c)
x
y
xy
x
y
.
See Solution
Problem 11603
In triangle
A
B
C
ABC
A
BC
, with
A
B
∥
A
C
AB \parallel AC
A
B
∥
A
C
, if
∠
B
A
C
=
5
x
\angle BAC = 5x
∠
B
A
C
=
5
x
and
∠
A
B
C
=
2
x
\angle ABC = 2x
∠
A
BC
=
2
x
, find
x
x
x
.
See Solution
Problem 11604
Calculate the BMI for a weight of
54
k
g
54 \mathrm{~kg}
54
kg
and a height of
1.42
m
1.42 \mathrm{~m}
1.42
m
.
See Solution
Problem 11605
Calculate the BMI for a weight of
42
k
g
42 \mathrm{~kg}
42
kg
and a height of
1.48
m
1.48 \mathrm{~m}
1.48
m
.
See Solution
Problem 11606
Find the limit:
lim
x
→
−
∞
x
6
−
3
x
4
2
x
2
−
2
x
+
1
\lim _{x \rightarrow-\infty} \frac{x^{6}-3 x^{4}}{2 x^{2}-2 x+1}
lim
x
→
−
∞
2
x
2
−
2
x
+
1
x
6
−
3
x
4
.
See Solution
Problem 11607
An oil spill spreads 25 m² every
1
6
\frac{1}{6}
6
1
hour. What is the total area after 2 hours?
See Solution
Problem 11608
In triangle
A
B
C
ABC
A
BC
, with points
D
D
D
on
A
B
AB
A
B
and
E
E
E
on
B
C
BC
BC
, find angles given
∠
A
B
C
=
2
8
∘
\angle ABC=28^{\circ}
∠
A
BC
=
2
8
∘
,
∠
B
E
D
=
3
8
∘
\angle BED=38^{\circ}
∠
BE
D
=
3
8
∘
.
(a) Find
∠
A
C
D
\angle ACD
∠
A
C
D
. (b) Express
∠
D
F
E
\angle DFE
∠
D
FE
in terms of
θ
\theta
θ
where
∠
C
A
E
=
θ
\angle CAE=\theta
∠
C
A
E
=
θ
.
See Solution
Problem 11609
Calculate the BMI for a person weighing
56
kg
56 \, \text{kg}
56
kg
and measuring
1.42
m
1.42 \, \text{m}
1.42
m
tall.
See Solution
Problem 11610
Find the distance a train travels in 3 hours if it goes 10 miles every
1
4
\frac{1}{4}
4
1
hour.
See Solution
Problem 11611
There are 180 white lockers and a ratio of 3:5 with blue lockers. Find the total number of lockers in the school.
See Solution
Problem 11612
What is the probability of seeing both a butterfly (80%) and a turtle (40%) during a nature center tour?
See Solution
Problem 11613
An oil spill spreads 25 m² every
1
6
\frac{1}{6}
6
1
hour. What is the area after 2 hours?
See Solution
Problem 11614
Estimate the number of employees out of 600 who read at least one book each month if
x
x
x
out of 50 do.
See Solution
Problem 11615
There are 180 white lockers. If there are 3 white lockers for every 5 blue lockers, how many total lockers are there?
See Solution
Problem 11616
Prove that
A
C
A
E
=
cos
ϕ
cos
θ
\frac{AC}{AE}=\frac{\cos \phi}{\cos \theta}
A
E
A
C
=
c
o
s
θ
c
o
s
ϕ
for rectangle
A
B
C
D
ABCD
A
BC
D
with point
E
E
E
on
B
C
BC
BC
.
See Solution
Problem 11617
Étudiez le cas où
b
1
=
b
2
=
b
\mathbf{b}_{1}=\mathbf{b}_{2}=\mathbf{b}
b
1
=
b
2
=
b
. Pour un disque de rayon
5
m
m
5 \mathrm{~mm}
5
mm
éclairant un disque de
5
c
m
5 \mathrm{~cm}
5
cm
à
50
c
m
50 \mathrm{~cm}
50
cm
, calculez les largeurs de l'ombre et de la pénombre à
2
m
2 \mathrm{~m}
2
m
. Expliquez les éclipses.
See Solution
Problem 11618
Calculate the BMI for weight
38
k
g
38 \mathrm{~kg}
38
kg
and height
151
c
m
151 \mathrm{~cm}
151
cm
.
See Solution
Problem 11619
In a regular
n
n
n
-sided polygon, the interior angle exceeds the exterior angle by
15
6
∘
156^{\circ}
15
6
∘
. Find
n
n
n
.
See Solution
Problem 11620
Find the supplementary angle to
(
11
x
+
3
)
∘
(11x+3)^\circ
(
11
x
+
3
)
∘
.
See Solution
Problem 11621
Solve the equation
∣
3
y
+
6
∣
=
13
|3y + 6| = 13
∣3
y
+
6∣
=
13
and select the solution set: A. List answers or B.
∅
\varnothing
∅
.
See Solution
Problem 11622
Kevin's age plus his age next year equals 69. How old will he be in 16 years?
See Solution
Problem 11623
Find two complementary angles where
(
2
x
−
9
)
∘
+
(
9
x
)
∘
=
9
0
∘
(2x-9)^{\circ} + (9x)^{\circ} = 90^{\circ}
(
2
x
−
9
)
∘
+
(
9
x
)
∘
=
9
0
∘
. Simplify your answers.
See Solution
Problem 11624
Find three consecutive even integers where the sum of the smallest and middle equals 44 more than the largest.
See Solution
Problem 11625
A customer slides a mug off a counter 1.38 m high, landing 0.80 m away. Find the exit velocity and impact direction (below horizontal).
See Solution
Problem 11626
Find the rotation rate in revolutions per second for a
32.5
f
t
32.5 \mathrm{ft}
32.5
ft
radius centrifuge to achieve
20.0
g
20.0 \mathrm{~g}
20.0
g
acceleration.
See Solution
Problem 11627
Find three consecutive odd integers where the sum of the smallest and middle integer equals 51 more than the largest.
See Solution
Problem 11628
39 feet of snow melts into how many inches of water? Use the ratio 1.5 feet snow = 2 inches water. Round to the nearest tenth.
See Solution
Problem 11629
How many inches will a 7-foot wall be represented in blueprints if studs are marked every 1.5 feet? Round to the nearest tenth.
See Solution
Problem 11630
Find the length of each side of an equilateral triangle with a perimeter of 31.5 inches. Each side is
x
x
x
inches.
See Solution
Problem 11631
A biologist tagged 168 fish, then caught 201 fish later, finding 22 tagged. Estimate the total fish using proportions.
See Solution
Problem 11632
Solve the equation
4
(
x
−
2
)
=
3
x
+
1
4(x-2)=3x+1
4
(
x
−
2
)
=
3
x
+
1
.
See Solution
Problem 11633
Find the length and width of a rectangular court where length is
9
9
9
ft longer than twice the width and perimeter is
108
108
108
ft.
See Solution
Problem 11634
If a store sells 129 ice cream cones, how many are vanilla if 1 in 3 buys vanilla? Round to the nearest whole number.
See Solution
Problem 11635
If 1 in 3 ice cream buyers chooses vanilla and a store sells 129 cones, how many are vanilla? Round to the nearest whole number.
See Solution
Problem 11636
Find the width and length of a rectangular area fenced along a river, where length is 7 ft more than width and total fencing is 91 ft.
See Solution
Problem 11637
Solve for
x
x
x
in the equation:
3
x
+
1
=
7
x
−
11
3 x + 1 = 7 x - 11
3
x
+
1
=
7
x
−
11
.
See Solution
Problem 11638
Solve the equation
26
+
1
=
76
−
11
26 + 1 = 76 - 11
26
+
1
=
76
−
11
. What is the value of the left side?
See Solution
Problem 11639
Find the probability that a randomly chosen employee has at least one child given they are married:
P
(
child
∣
married
)
\mathrm{P}(\text{child} | \text{married})
P
(
child
∣
married
)
.
See Solution
Problem 11640
Travis has a 4" x 6" photo. a) If enlarged to 16" wide, what is the new height? b) Can it be enlarged to 8" x 10"? Answer y or
n
n
n
.
See Solution
Problem 11641
If 45 teaspoons of vegetable oil are used, how many teaspoons of vinegar are needed based on the ratio
9
:
6
9:6
9
:
6
?
See Solution
Problem 11642
See Solution
Problem 11643
Nick needs to find how much vinegar for 12 cups of olive oil if he uses
1
4
\frac{1}{4}
4
1
cup per cup of oil. A. 6 cups B.
2
1
2
2 \frac{1}{2}
2
2
1
cups C.
5
1
4
5 \frac{1}{4}
5
4
1
cups D. 3 cups
See Solution
Problem 11644
What operation isolates
x
x
x
in
8
x
=
72
8 x=72
8
x
=
72
? Options: A. +8 B.
×
1
8
\times \frac{1}{8}
×
8
1
C. ÷8 D. ÷72 E. ÷
8
x
8x
8
x
F.
×
\times
×
8 G. -
8
x
8x
8
x
. Also, solve
8
x
=
72
8x=72
8
x
=
72
:
x
=
x=
x
=
help (numbers).
See Solution
Problem 11645
Solve the equation:
2
(
2
x
+
7
)
=
11
x
2(2 x+7)=11 x
2
(
2
x
+
7
)
=
11
x
.
See Solution
Problem 11646
Solve
x
+
7
5
=
15
\frac{x+7}{5}=15
5
x
+
7
=
15
by stating the order of two operations. Then, find
x
x
x
. What is
x
=
□
x=\square
x
=
□
?
See Solution
Problem 11647
Find the probability
P
\mathrm{P}
P
(pool | not two-story) given
60
%
60\%
60%
two-story,
24
%
24\%
24%
with a pool,
15
%
15\%
15%
both.
See Solution
Problem 11648
Find the width and length of a rectangular area fenced along a river, where length is 7 ft greater than width, using 91 ft of fencing.
See Solution
Problem 11649
Calculate the total cost for 32 guests at an ice cream social with a \$40 shelter fee and \$9 per guest.
See Solution
Problem 11650
Write a linear equation for total cost
y
y
y
with
x
x
x
guests, given shelter cost is \$40 and ice cream is \$9 per guest.
See Solution
Problem 11651
Destiny's ice cream social costs \$ 40 plus \$ 9 per guest. Find guests if the total bill is \$ 256.
See Solution
Problem 11652
Find the probability
P
\mathrm{P}
P
(pass
∣
\mid
∣
girl) given 50 girls passed and total students is 120.
See Solution
Problem 11653
Find the line equation through
(
−
4
,
1
)
(-4,1)
(
−
4
,
1
)
that is perpendicular to
−
3
x
+
4
y
=
9
-3x + 4y = 9
−
3
x
+
4
y
=
9
.
See Solution
Problem 11654
Solve the equation:
9
x
−
3
=
3
(
2
x
+
5
)
9x - 3 = 3(2x + 5)
9
x
−
3
=
3
(
2
x
+
5
)
.
See Solution
Problem 11655
Find the value of
x
x
x
in the equation
2
+
279
=
x
2 + 279 = x
2
+
279
=
x
.
See Solution
Problem 11656
Find the weight range
w
w
w
for a healthy BMI (19-25) at heights: (a) 75 in., (b) 74 in., (c) 78 in. Round to nearest lb.
See Solution
Problem 11657
The sides of a triangle are in a ratio of
2
:
3
:
4
2:3:4
2
:
3
:
4
. If the perimeter is
63
63
63
in, find the longest side.
See Solution
Problem 11658
Amir buys 3 cakes at
c
c
c
cents each and 2 loaves at
(
2
c
−
11
)
(2c-11)
(
2
c
−
11
)
cents. Total spent is \
5.87.
F
i
n
d
5.87. Find
5.87.
F
in
d
c$.
See Solution
Problem 11659
Let
x
x
x
be the unknown. Write and solve the equation:
x
+
5
=
−
25
x + 5 = -25
x
+
5
=
−
25
.
See Solution
Problem 11660
Solve the equation
C
=
π
d
C=\pi d
C
=
π
d
for
d
d
d
. What is
d
d
d
in terms of
C
C
C
?
See Solution
Problem 11661
Solve for
x
x
x
:
0.72
x
−
0.93
=
9.39
−
3.58
x
0.72 x - 0.93 = 9.39 - 3.58 x
0.72
x
−
0.93
=
9.39
−
3.58
x
See Solution
Problem 11662
Solve
1
3
∣
3
x
+
9
∣
−
5
=
4
\frac{1}{3}|3 x+9|-5=4
3
1
∣3
x
+
9∣
−
5
=
4
. What are the possible values of
x
x
x
?
See Solution
Problem 11663
Calculate
18
−
0
18 - 0
18
−
0
. What is the result?
See Solution
Problem 11664
Write an equation for "The sum of a number and 5 is -25" and solve for
x
x
x
. What is the equation?
See Solution
Problem 11665
If total rainfall is
7
/
16
7/16
7/16
inch, how much fell in the second half of the month? Answer as a fraction or mixed number.
See Solution
Problem 11666
Find the weight range
w
w
w
(to nearest pound) for a healthful BMI (19-25) using
B
M
I
=
704
×
(
weight
)
(
height
)
2
BMI=\frac{704 \times(\text{weight})}{(\text{height})^2}
BM
I
=
(
height
)
2
704
×
(
weight
)
. Heights: (a) 66 in, (b) 78 in, (c) 73 in.
See Solution
Problem 11667
Solve the equation:
7
⋅
−
3
5
+
−
3
5
=
0
7 \cdot \frac{-3}{5} + \frac{-3}{5} = 0
7
⋅
5
−
3
+
5
−
3
=
0
.
See Solution
Problem 11668
Calculate the total cost for
5
3
4
5 \frac{3}{4}
5
4
3
pounds of beef at \$4.99 per pound.
See Solution
Problem 11669
Calculate the volume of a rectangular prism with length
14.25
ft
14.25 \, \text{ft}
14.25
ft
, width
13
ft
13 \, \text{ft}
13
ft
, and height
4
1
5
ft
4 \frac{1}{5} \, \text{ft}
4
5
1
ft
using
V
=
l
w
h
V=lwh
V
=
lw
h
.
See Solution
Problem 11670
Ian's diet is
30
%
30\%
30%
fat and
50
%
50\%
50%
carbs. If he eats
3
,
000
k
c
a
l
3,000 \mathrm{kcal}
3
,
000
kcal
, what % of protein is he consuming? a)
10
%
10\%
10%
b)
20
%
20\%
20%
c)
30
%
30\%
30%
d)
40
%
40\%
40%
See Solution
Problem 11671
Find
R
S
R S
RS
if
S
S
S
is the midpoint of
R
T
‾
\overline{R T}
RT
,
R
S
=
5
x
+
17
R S=5 x+17
RS
=
5
x
+
17
, and
S
T
=
8
x
−
31
S T=8 x-31
ST
=
8
x
−
31
.
See Solution
Problem 11672
An alloy is made by mixing 28g of 15% copper and 100g of 55% copper. Find the grams and percentage of copper in the mixture.
See Solution
Problem 11673
Nicole and Chris each deposit \$90,000 at 3\% interest. Calculate their interest for the first three years and compare.
See Solution
Problem 11674
Determine the other trigonometric functions for
θ
\theta
θ
given that
tan
θ
=
−
1
6
\tan \theta=-\frac{1}{6}
tan
θ
=
−
6
1
and
sin
θ
>
0
\sin \theta>0
sin
θ
>
0
.
See Solution
Problem 11675
Nicole and Chris each deposit \$20,000 at 2\% interest. Find their earnings for 3 years and compare.
See Solution
Problem 11676
If
J
L
=
10
x
−
2
J L=10 x-2
J
L
=
10
x
−
2
,
J
K
=
5
x
−
8
J K=5 x-8
J
K
=
5
x
−
8
, and
K
L
=
7
x
−
12
K L=7 x-12
K
L
=
7
x
−
12
, what is the value of
K
L
K L
K
L
?
See Solution
Problem 11677
Ian's diet has
30
%
30\%
30%
Fat and
50
%
50\%
50%
Carbs in a total of
3
,
000
k
c
a
l
3,000 \mathrm{kcal}
3
,
000
kcal
. How many kcal is he getting from Protein? a)
400
k
c
a
l
400 \mathrm{kcal}
400
kcal
b)
500
k
c
a
l
500 \mathrm{kcal}
500
kcal
c)
600
k
c
a
l
600 \mathrm{kcal}
600
kcal
d)
700
k
c
a
l
700 \mathrm{kcal}
700
kcal
See Solution
Problem 11678
Alonzo deposited \$12,000 at 6% and \$4,000 at 5%. Find: (a) total interest after 1 year and (b) total percent interest earned.
See Solution
Problem 11679
Ian's diet is 30% fat, 50% carbs, and 20% protein from 3000 kcal. How many grams of protein is he eating? Options: a) 150 b) 200 c) 300.
See Solution
Problem 11680
Karen invested \$3000 at 5\% and \$7000 at 4\%. Find total interest after 1 year and overall percent interest.
See Solution
Problem 11681
Laura and Eric each deposit \$70,000 at 6\% interest. Calculate their yearly interest for 3 years and compare.
See Solution
Problem 11682
Debra deposits \$30,000 at 4\% compounded annually, while Dan uses simple interest. Calculate their interest for 3 years and compare.
See Solution
Problem 11683
Debra and Dan each deposit \$30,000 at 4\% interest. Calculate their yearly interest for 3 years and compare.
See Solution
Problem 11684
Find angles
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
where
∠
2
\angle 2
∠2
is supplementary to
∠
1
\angle 1
∠1
and
m
∠
2
=
2
m
∠
1
+
3
6
∘
m \angle 2 = 2m \angle 1 + 36^\circ
m
∠2
=
2
m
∠1
+
3
6
∘
.
See Solution
Problem 11685
Find angles
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
where
∠
2
\angle 2
∠2
is a supplement and
3
6
∘
36^{\circ}
3
6
∘
more than
2
×
∠
1
2 \times \angle 1
2
×
∠1
.
See Solution
Problem 11686
Amy deposits \$60,000 at 3\% annual compound interest, Bill at 3\% simple interest. Calculate their interest for 3 years.
See Solution
Problem 11687
Ian's diet has 30% fat and 50% carbs in 3,000 kcal. How many kcal are from carbs? a) 500 b) 1000 c) 1500 d) 2000
See Solution
Problem 11688
Un poisson voit un disque lumineux de rayon
r
=
3.0
m
r=3.0 \, m
r
=
3.0
m
à la surface d'un lac (indice
n
=
1.33
n=1.33
n
=
1.33
). Quelle est sa profondeur?
See Solution
Problem 11689
Lena deposited \$5000 at a 4.4% annual interest rate, compounded quarterly. How long to grow to \$6000? Round to the nearest hundredth.
See Solution
Problem 11690
Solve for
h
h
h
in the equation
A
=
1
2
(
B
+
b
)
h
A=\frac{1}{2}(B+b) h
A
=
2
1
(
B
+
b
)
h
.
See Solution
Problem 11691
Ian's diet has
30
%
30\%
30%
fat and
50
%
50\%
50%
carbs in a
3
,
000
k
c
a
l
3,000 \mathrm{kcal}
3
,
000
kcal
total. How many grams of carbs is he eating? a) 375 b) 400 c) 425 d) 450
See Solution
Problem 11692
Jessica and Tom each deposit \$10,000 at 2% interest. Calculate their interest for 3 years and compare who earns more each year.
See Solution
Problem 11693
Find
D
E
D E
D
E
given that
B
B
B
is the midpoint of
A
C
A C
A
C
,
A
C
=
C
D
A C=C D
A
C
=
C
D
,
A
B
=
3
x
+
4
A B=3 x+4
A
B
=
3
x
+
4
,
A
C
=
11
x
−
17
A C=11 x-17
A
C
=
11
x
−
17
, and
C
E
=
49
C E=49
CE
=
49
.
See Solution
Problem 11694
Solve the equation
5
x
2
−
x
−
7
=
0
5 x^{2}-x-7=0
5
x
2
−
x
−
7
=
0
. It cannot be factored.
See Solution
Problem 11695
Balance the equation:
C
a
3
(
P
O
4
)
2
(
s
)
+
S
i
O
2
(
s
)
+
C
(
s
)
→
C
a
S
i
O
3
(
s
)
+
P
4
(
s
)
+
C
O
(
g
)
\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+\mathrm{SiO}_{2}(s)+\mathrm{C}(s) \rightarrow \mathrm{CaSiO}_{3}(s)+\mathrm{P}_{4}(s)+\mathrm{CO}(g)
Ca
3
(
PO
4
)
2
(
s
)
+
SiO
2
(
s
)
+
C
(
s
)
→
CaSiO
3
(
s
)
+
P
4
(
s
)
+
CO
(
g
)
using smallest whole number coefficients.
See Solution
Problem 11696
Balance the equation:
C
a
3
(
P
O
4
)
2
(
s
)
+
S
i
O
2
(
s
)
+
C
(
s
)
→
3
C
a
S
i
O
3
(
s
)
+
P
4
(
s
)
+
C
O
(
g
)
\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+\mathrm{SiO}_{2}(s)+\mathrm{C}(s) \rightarrow 3 \mathrm{CaSiO}_{3}(s)+\mathrm{P}_{4}(s)+\mathrm{CO}(g)
Ca
3
(
PO
4
)
2
(
s
)
+
SiO
2
(
s
)
+
C
(
s
)
→
3
CaSiO
3
(
s
)
+
P
4
(
s
)
+
CO
(
g
)
See Solution
Problem 11697
Solve
(
x
+
2
)
2
=
49
(x+2)^{2}=49
(
x
+
2
)
2
=
49
. Hint: 49 is a perfect square.
See Solution
Problem 11698
Solve
x
2
+
4
x
=
−
1
x^{2}+4 x=-1
x
2
+
4
x
=
−
1
. Hint: Add 4 to both sides to form a perfect square.
See Solution
Problem 11699
Chang's trip to the mountains took 7 hours; the return took 5 hours at 18 mph faster. Find the distance to the mountains.
See Solution
Problem 11700
Solve for
x
x
x
if
∠
N
K
L
=
3
x
−
10
\angle NKL = 3x - 10
∠
N
K
L
=
3
x
−
10
and
∠
N
K
M
=
2
x
+
20
\angle NKM = 2x + 20
∠
N
K
M
=
2
x
+
20
, with KN bisecting
∠
L
K
M
\angle LKM
∠
L
K
M
.
See Solution
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