Statistical Inference

Problem 501

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Fake Twitter followers: Many celebrities and public figures have Twitter accounts with large numbers of followers. However, some of these followers are fake, resulting from accounts generated by spamming computers. In a sample of 64 twitter audits, the mean percentage of fake followers was 14.6 with a standard deviation of 10.6 .
Part 1 of 2 (a) Construct a $99.5 \%$ confidence interval for the mean percentage of fake Twitter followers. Round the answers to at least one decimal place,
A $99.5 \%$ confidence interval for the mean percentage of fake Twitter followers is $10.7<\mu<18.5$ .
Part: $1 / 2$
Part 2 of 2 (b) Based on the confidence interval, is it reasonable that the mean percentage of fake Twitter followers is less than 9?
It (Choose one) $\boldsymbol{\nabla}$ reasonable that the mean percentage of fake Twitter followers is less than 9 . Save For Later Submit Assignme Check - 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use| Privacy Center| Accessi

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Problem 502

www-awu.aleks.com s Bettin Secret - Goo... Home - Nort... Content ChatGPT Chicago B. Failed to ope. Oniline Bertin. (5) KaCe Homework \& 4: $7(1,2,3,4) 8(2,3,4)$ Question 28 of 40 (1 point) I Question Attempt: 1 of 3 21 22 23 25 26 27 $=28$ 29 30 Jonathan
Baby weights: Following are weights, in pounds, of 10 two-month-old baby girls. It is reasonable to assume that the population is approximately normal. \begin{tabular}{ccccc} \hline 12.32 & 11.87 & 12.34 & 11.48 & 12.66 \\ 8.51 & 14.13 & 12.95 & 9.34 & 8.63 \\ \hline \end{tabular} Send data to Excel (a) Construct a $90 \%$ confidence interval for the mean weight of two-month-old baby girls. (b) According to the National Health Statistics Reports, the mean weight of two-month-old baby boys is 13.9 pounds. Based on the confidence interval, is it reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys? Explain.
Part 1 of 2 (a) A $90 \%$ confidence interval for the mean weight of two-month-old baby girls is $10.307<\mu<12.539$ .
Part: $1 / 2$
Part 2 of 2 (b) It (Choose one) $\boldsymbol{\nabla}$ reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys. Skip Part Check Save For Later Submit Assi - 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use 1 Pivacy Center $\quad$ t

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Problem 503

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Smart phone: Among 240 cell phone owners aged 18-24 surveyed, 108 said their phone was an Android phone. Perform the following.
Part: $0 / 3$
Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places.
The point estimate for the proportion of cell phone owners aged 18 - 24 who have an Android phone is $\square$ . Skip Part Check Save For Later Submit Assi - 2024 MaGraw Hill LLC. All Righis Resenced, Terms of Use 1 Pinasy Center

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Problem 504

www-awu.aleks.com Secret - GoO. Home - Nort Content ChatGPT Chicago B.. Failed to ope... Online Bettin... (5) KaiCe... Homework \ $4: 7(1,2,3,4) 8(2,3,4) Question 30 of 40 (1 point) I Question Attempt: 1 of 3 Jonathan$ \checkmark 23 $24 25 26 27 28 29$ \equiv 30$ 31 32 Esparí 33
Smart phone: Among 240 cell phone owners aged 18-24 surveyed, 108 said their phone was an Android phone. Perform the following.
Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have àn Android phone. Round the answer to at least three decimal places.
The point estimate for the proportion of cell phone owners aged 18 - 24 who have an Android phone is 0.450 .
Part: $1 / 3$
Part 2 of 3 (b) Construct a $90 \%$ confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places.
A $90 \%$ confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone is $\square$ $<p<$ $\square$ . Skip Part Check Save For Later Submit Assignr Q 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center I Acce

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Problem 505

www-awuialeks.com Secret - Coo... 11/22/24 ATL... Home - Nort... Content ChatGPT Chicago B... Failed to ope... Online Bettin... (6) KaiCe. Homework * 4: $7(1,2,3,4) 8(2,3,4)$ Question 30 of 40 (1 point) I Question Attempt: 1 of 3 Jonath
Smart phone: Among 240 cell phone owners aged 18-24 surveyed, 108 said their phone was an Android phone. Perform the following.
Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places.
The point estimate for the proportion of cell phone owners aged $18-24$ who have android phone is 0.450 .
Part 2 of 3 (b) Construct a $90 \%$ confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places.
A $90 \%$ confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone is $0.397<p<0.503$
Part: $2 / 3$
Part 3 of 3 (c) Assume that an advertisement claimed that $38 \%$ of cell phone owners aged 18-24 have an Android phone. Does the confidence interval contradict this claim? claim?
The confidence interval $\square$ (Choose one) contradict the claim, because 0.38 (Choose one) contained in the confidence interval. Skip Part Check Save For Later Submit Assignm ( 2024 MaGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center I Acces:

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Problem 506

Homework * 4: $7(1,2,3,4) 8(2,3,4)$ Question 32 of 40 (1 point) I Question Attempt: 1 of 3 Jonathan 2 23 24 25 26 28 29 30 $\checkmark 31$ $=32$ Español 33
Sleep apnea: Sleep apnea is a disorder in which there are pauses in breathing during sleep. People with this condition must wake up frequently to breathe. In a sample of 420 people aged 65 and over, 114 of them had sleep apnea.
Part 1 of 3 (a) Find a point estimate for the population proportion of those aged 65 and over who have sleep apnea. Round the answer to three decimal places.
The point estimate for the population proportion of those aged 65 and over who have sleep apnea is 0.271 .
Part 2 of 3 (b) Construct a $99.8 \%$ confidence interval for the proportion of those aged 65 and over who have sleep apnea. Round the answer to three decimal places.
A $99.8 \%$ confidence interval for the proportion of those aged 65 and over who have sleep apnea is $0.204<p<0.338$ .
Part: $2 / 3$
Part 3 of 3 (c) In another study, medical researchers concluded that more than $12 \%$ of elderly people have sleep apnea. Based on the confidence interval, does it appear that more than $12 \%$ of people aged 65 and over have sleep apnea? Explain.
Since all of the values in the confidence interval are $\square$ 0.12 , the confidence interval (Choose one) contradict the claim. $\square$ Skip Part Check Save For Later Submit Assignment - 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center I Accessibili

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Problem 507

www-awu.aleks.com d Onlin. Sports Betting Secret -... 11/22/24 ATL @ CHI /// St... Home - Northern Essex... Content A ALEKS - Jonathan Vega... ChatGPT (5) KaiCenat - T Homework * $4: 7(1,2,3,4) 8(2,3,4)$ Question 34 of 40 (1 point) I Question Attempt: 1 of 3 Jonathan 2 23 24 25 26 27 28 29 30 31 $\checkmark 32$ Españo 33
Volunteering: The General Social Survey asked 1305 people whether they performed any volunteer work during the past year. A total of 522 people said they did.
Part 1 of 3 (a) Find a point estimate for the proportion of people who performed volunteer work during the past year. Round the answer to at least three decimal places.
The point estimate for the proportion of people who performed volunteer work during the past year is $\square$ 0.4000
Alternate Answer: 0.4
Part: $1 / 3$
Part 2 of 3 (b) Construct a $95 \%$ confidence interval for the proportion of people who performed volunteer work during the past year. Round the answer to at least three decimal places.
A $95 \%$ confidence interval for the proportion of people who performed volunteer work during the past year is $\square$ $<p<$ $\square$ Skip Part Check Save For Later Submit Assignmen 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center I Accessibil

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Problem 508

ww-awu-aleks.com its Bexting and Onlin. Sports Betting Secrot -... 11/22/24 ATL C CHI /// St. Homo - Northern Essex. Content A ALEKs - Jonathen Vcga. ChatGPT (5) XaiCenat - Twitch Homework $\& 4: 7(1,2,3,4) 8(2,3,4)$ Question 34 of 40 (1 point) 1 Question Attempt: 1 of 3 Jonathan
Volunteering: The General Social Survey asked 1305 people whether they performed any volunteer work during the past year. A total of 522 people said they Español did.
Part 1 of 3 (a) Find a point estimate for the proportion of people who performed volunteer work during the past year. Round the answer to at least three decimal places.
The point estimate for the proportion of people who performed volunteer work during the past year is 0.4000 .
Alternate Answer: 0.4
Part 2 of 3 (b) Construct a $95 \%$ confidence interval for the proportion of people who performed volunteer work during the past year. Round the answer to at least three decimal places.
A $95 \%$ confidence interval for the proportion of people who performed volunteer work during the past year is $0.3737<p<0.4263$ .
Part: $2 / 3$
Part 3 of 3 (c) A sociologist states that $46 \%$ of Americans perform volunteer work in a given year. Does the confidence interval contradict this statement? Explain.
The confidence interval (Choose one) $\square$ contradict the claim, because 0.46 (Choose one) $\square$ contained in the confidence interval. Skip Part Check Save For Later Submit Assignment - 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center I Accessibitity

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Problem 509

www-awu.aleks.com and Onlin. Sports Betting Secret - 11/22/24 ATL @ CHI III St... Home - Northern Essex... Content A Aleks - Jonathan Voga... ChatGPT (5) KaiCenat - Twitch Homework * 4: $7(1,2,3,4) 8(2,3,4)$ Question 35 of 40 (1 point) 1 Question Attempt: 1 of 3 Jonathan 2 23 24 25 26 27 28 29 30 31 32 Español 33
Contaminated water: In a sample of 44 water specimens taken from a construction site, 27 contained detectable levels of lead.
Part 1 of 3 (a) Construct a $95 \%$ confidence interval for the proportion of water specimens that contain detectable levels of lead. Round the answer to at least three decimal places.
A $95 \%$ confidence interval for the proportion of water specimens that contain detectable levels of lead is $0.471<p<0.757$ .
Part: $1 / 3$
Part 2 of 3 (b) Construct an $80 \%$ confidence interval for the proportion of water specimens that contain detectable levels of lead. Round the answer to at least three decimal places.
An $80 \%$ confidence interval for the proportion of water specimens that contain detectable levels of lead is $\square$ $<p<$ $\square$ . Skip Part Check Save For Later Submit Assignment - 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use T Privacy Center I Accessibility

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Problem 510

ww-awu-aleks.com letting and Onlin Sports Betting Secret -m. 1122/24 ATL @CHI III St... Home - Northern Essex... Contont A) ALeks - Jonathan Voga.. ChatGPT (5) KaiConat - Twitch Homework * 4: $7(1,2,3,4) 8(2,3,4)$ Question 36 of 40 (1 point) I Question Attempt: 1 of 3 Jonathan 2 23 24 25 26 27 28 29 30 31 $\checkmark 2$ Español 133
Changing jobs: A sociologist sampled 214 people who work in computer-related jobs, and found that 44 of them have changed jobs in the past 6 months. Part: $0 / 2$ $\square$
Part 1 of 2 (a) Construct a $99.8 \%$ confidence interval for those who work in computer-related jobs who have changed jobs in the past 6 months. Round the answer to at least three decimal places.
A $99.8 \%$ confidence interval for the proportion of those who work in computer-related jobs who have chaneed jobs in the past 6 months is $0.2056^{\boldsymbol{\alpha}}<p<0.0843$ .

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Problem 511

www-awu.aleks.com Sports Betting Secret -... 11/22/24 ATL @ CHI /// St... Home - Northern Essex... Content ChatGPT (5) KaiCenat - Twitch Homework \# 4: 7(1,2,3,4) 8(2,3,4) Question 36 of 40 (1 point) I Question Attempt: 1 of 3 2 23 24 25 26 27 28 29 30 Español Jonathan
Changing jobs: A sociologist sampled 214 people who work in computer-related jobs, and found that 44 of them have changed jobs in the past 6 months. Part 1 of 2 (a) Construct a $99.8 \%$ confidence interval for those who work in computer-related jobs who have changed jobs in the past 6 months. Round the answer to at least three decimal places.
A $99.8 \%$ confidence interval for the proportion of those who work in computer-related jobs who have changed jobs in the past 6 months is 0.1203 $\square$
Part: $1 / 2$
Part 2 of 2 (b) Among the 214 people, 128 of them are under the age of 35 . These constitute a simple random sample of workers under the age of 35. If this sample were used to construct a $99.8 \%$ confidence interval for the proportion of workers under the age of 35 who have changed jobs in the past 6 months, is it likely that the margin of error would be larger, smaller, or about the same as the one in Part (a)?
The margin of error would be (Choose one) $\square$ , because the size of the sample is $\square$ (Choose one) . Skip Part Check Save For Later Submit Assignment

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Problem 512

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Homework \# 4: $7(1,2,3,4) 8(2,3,4)$ Question 39 of 40 (1 point) | Question Attempt: 1 of 3 29 30 $\checkmark 31$ 33 34 35 36 37 38
IQ scores: Scores on an IQ test are normally distributed. A sample of 8 IQ scores had standard deviation $s=6$ . (a) Construct a $95 \%$ confidence interval for the population standard deviation $\sigma$ . Round the answers to at least two decimal places. (b) The developer of the test claims that the population standard deviation is $\sigma=7$ . Does this confidence interval contradict this claim? Explain.
Part: $0 / 2$
Part 1 of 2
A $95 \%$ confidence interval for the population standard deviation is $3.97<\sigma<10.79$ .

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Problem 513

Question 2
Less than 39\% of workers got their job through newspaper ads. Express the null and alternative hypotheses in symbolic form for this claim (enter as a percentage). $\begin{array}{l} H_{0}: p \square \\ H_{1}: p \square \end{array}$
Use the following codes to enter the following symbols: $\begin{array}{l} \geq \text { enter }>= \\ \leq \text { enter }<= \\ \neq \text { enter }!= \end{array}$

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Problem 514

The $p$ -value for a hypothesis test turns out to be 0.051785. At a 7\% level of significance, what is the proper decision? Fail to reject $H_{0}$ Reject $H_{0}$

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Problem 515

The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 40 who smoke. Step 2 of 2: Suppose a sample of 1548 Americans over 40 is drawn. Of these people, 1100 don't smoke. Using the data, construct the $99 \%$ confidence interval for the population proportion of Americans over 40 who smoke. Round your answers to three decimal places.

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Problem 516

10:4/PM Fri Nov 22
You wish to test the following claim ( $H_{a}$ ) at a significance level of $\alpha=0.01$ . $\begin{array}{l} H_{o}: \mu=83.5 \\ H_{a}: \mu \neq 83.5 \end{array}$
You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size $n=556$ with mean $\bar{x}=85.4$ and a standard deviation of $s=16.7$ .
What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = $\square$
What is the $p$ -value for this sample? (Report answer accurate to four decimal places.) p -value = $\square$ The $p$ -value is... less than (or equal to) $\alpha$ greater than $\alpha$
This test statistic leads to a decision to... reject the null accept the null fail to reject the null
As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 83.5 . There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 83.5 . The sample data support the claim that the population mean is not equal to 83.5. There is not sufficient sample evidence to support the claim that the population mean is not equal to 83.5 . Check Answer

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Problem 517

iven in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally istributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. Submit t InIS test: 20 point(S) possible This question: 4 point(s) possible \begin{tabular}{|c|c|r|} \hline & Male BMI & Femal \\ \hline $\boldsymbol{\mu}$ & $\mu_{1}$ & $\mu_{2}$ \\ \hline $\bar{n}$ & 49 & 49 \\ \hline $\bar{x}$ & 27.8756 & 26.07 \\ \hline s & 8.866451 & 4.1461 \\ \hline \end{tabular} - Test the claim that males and females have the same mean body mass index (BMI).
That are the null and alternative hypotheses? A $\begin{array}{l} H_{0}: \mu_{1}=\mu_{2} \\ H_{1}: \mu_{1} \neq \mu_{2} \end{array}$ B. $H_{0}: \mu_{1} \neq \mu_{2}$ $H_{1}: \mu_{1}<\mu_{2}$ C $\begin{array}{l} H_{0}: \mu_{1}=\mu_{2} \\ H_{1}: \mu_{1}>\mu_{2} \end{array}$ D. $H_{0}: \mu_{1} \geq \mu_{2}$ $H_{1}: \mu_{1}<\mu_{2}$ he test statistic, t , is $\square$ . (Round to two decimal places as needed.) he $P$ -value is $\square$ (Round to three decimal places as needed.) tate the conclusion for the test. A. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. B. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. C. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. Next

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Problem 518

Student/PlayerTest.aspx?canvas_workflow_statesavailable\&canvas_enrollment_state=active\&canvas_user_id=3490178canvas_module_id=9590348canvas_assignment_points kriscia mejia Question 1 of 5 This test: 20 point(s) possible This question: 4 point(s) possible Submit test ven in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally tributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. c. $H_{0}: \mu_{1}=\mu_{2}$ \begin{tabular}{|c|c|c|} \hline & Male BMI & Female BMI \\ \hline $\boldsymbol{\mu}$ & $\mu_{1}$ & $\mu_{2}$ \\ \hline $\boldsymbol{n}$ & 49 & 49 \\ \hline $\bar{x}$ & 27.8756 & 26.0709 \\ \hline $s$ & 8.866451 & 4.146108 \\ \hline \end{tabular} $H_{1}: \mu_{1}>\mu_{2}$ D. $H_{0}: \mu_{1} \gtrless \mu_{2}$ $H_{1}: \mu_{1}<\mu_{2}$ est statistic, $t_{\text {t }}$ is 1.29 . (Round to two decimal places as needed.) -value is 0.202 . (Round to three decimal places as needed.) the conclusion for the test.
Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. eject the null hypothesis. There is sufficient evidence to warrant reje tejection of the claim that men and women have the same mean BMI. of the claim that men and women have the salme mean BMI. $-\mu_{2}<\Pi$

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Problem 519

57 Replies, 57. Unread
Discussion: Hypothesis Testing: One Sample Instruction: Post your response first and then reply to two of your colleagues' posts. - Explain the difference between the z-test for mean using a P-Value and the z-test for mean using the rejection region(s).

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Problem 520

Explain the conditions that are necessary to use the $t$ -test to test the difference between two population means.

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Problem 521

Question 17, 7.1.18 Part 1 of 2 HW Score: 65.65\%, 15.1 of 23 poir Points: 0 of 1
A genetic experiment with peas resulted in one sample of offspring that consisted of 433 green peas and 163 yellow peas. a. Construct a $95 \%$ confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that $25 \%$ of the offispring peas would be yellow? a. Construct a 95\% confidence interval. Express the percentages in decimal form. $\square$ $<p<$ $\square$ (Round to three decimal places as needed.)

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Problem 522

Assume that you plan to use a significance level of $\alpha=0.05$ to test the claim that $p_{1}=p_{2}$ . Use the given sample sizes and numbers of successes to find the p-value for the hypothesis test. $\begin{array}{l} n_{1}=100, n_{2}=100 \\ x_{1}=38, x_{2}=40 \end{array}$ A. 0.2130 B. 0.0412 C. 0.7718 D. 0.1610

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Problem 523

Q1(6). Parents were asked if sports are equally important for boys and girls. Suppose that the proportion of parents who agree the equal importance in the population is actually 0.65 . In a survey, of the 400 parents interviewed, $70 \%$ agreed that boys and girls should have equal opportunities to participate in sports.
1(2). Describe the sampling distribution of the sample proportion of parents who agree that boys and girls should have equal opportunities.
2(4). What is the probability of observing a sample proportion as large as or larger than the observed value $\hat{p}$ $=0.70 ?$

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Problem 524

varince
A simple random sample of 31 men from a normally distributed population results in a standard deviation of 10.7 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. Complete parts (a) through (d) below. a. Identify the null and alternative hypotheses. Choose the correct answer below. A. $H_{0}: \sigma \neq 10$ beats per minute B. $H_{0}: \sigma=10$ beats per minute $H_{1}: \sigma=10$ beats per minute $H_{1}: \sigma<10$ beats per minute C. $H_{0}: \sigma=10$ beats per minute D. $H_{0}: \sigma \geq 10$ beats per minute $H_{1}: \sigma \neq 10$ beats per minute $H_{1}: \sigma<10$ beats per minute b. Compute the test statistic. $x^{2}=\square$ (Round to three decimal places as needed.)

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Problem 525

Part 2 of 2
Claim: A majority of adults would erase all of their personal information online if they could. A software firm survey of 528 randomly selected adults showed that $57 \%$ of them would erase all of their personal information online if they could. Complete parts (a) and (b) below. a. Express the original claim in symbolic form. Let the parameter represent the adults that would erase their personal information. p 0.5 (Type an integer or a decimal. Do not round.) b. Identify the null and alternative hypotheses. $\mathrm{H}_{0}$ : $\square$ $\square$ $\square$ $\mathrm{H}_{1}$ : $\square$ $\square$ (Type integers or decimals. Do not round.)

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Problem 526

In a recent Super Bowl, a TV network predicted that $39 \%$ of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 144 people who saw the commercials and found that 50 of them said they would watch one of the television shows.
Suppose you are have the following null and alternative hypotheses for a test you are running: $\begin{array}{c} H_{0}: p=0.39 \\ H_{a}: p<0.39 \end{array}$
Calculate the test statistic, rounded to 3 decimal places $z=\square$

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Problem 527

You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.73 . You use a significance level of $\alpha=0.05$ . $\begin{array}{l} H_{0}: p=0.73 \\ H_{1}: p>0.73 \end{array}$
You obtain a sample of size $n=210$ in which there are 167 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic $=$ $\square$ What is the $p$ -value for this sample? (Report answer accurate to four decimal places.) p -value = $\square$

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Problem 528

Two types of medicines are being tested in their effectiveness at reducing migraines. Two random samples of 200 patients were each given either Medicine A or Medicine B. In the group given Medicine A, 23 reported no headache after 30 minutes and in the group given Medicine B, 50 reported no headache after 30 minutes.
Complete the setup for a hypothesis test at $1 \%$ level of signficance to determine if there is a difference in the proportion of relieved headaches. You may use the Compare Two Population Proportions tool.
Identify the null and alternative hypothesis. The null hypothesis is $H_{0}: p_{A}>p_{B}$ $H_{0}: p_{A}<p_{B}$ $H_{0}: p_{A}=p_{B}$ $H_{0}: p_{A} \neq p_{B}$ The alternative hypothesis is $H_{A}: p_{A}>p_{B}$ $H_{A}: p_{A}<p_{B}$ $H_{A}: p_{A}=p_{B}$ $H_{A}: p_{A} \neq p_{B}$
Round your answers to three decimal places.
The pooled proportion is $p_{c}=$ $\square$ , the standard error is $\mathrm{SE}=$ $\square$ and the test statistic is $z=$ $\square$ We will use a Select an answer test.

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Problem 529

ANOVA Aaxiety Leve! \begin{tabular}{ll|l|l|l|l} & \begin{tabular}{l} Sum of \\ Squares \end{tabular} & df & & Mean Square & $F$ \end{tabular} - Interpret these results by explaining if there is a significant difference between any of the groups, and if so, how you can tell. - Reflect on these results and how they fit with your own experiences and expectations. - Discuss any limitations of ANOVA and explain how they relate to this situation.

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Problem 530

isiah cromer Homework: Homework 10 Question 3, 13.2.4 Part 3 of 4 HW Score: $5.56 \%, 1.17$ of 21 points Points: 0 of 3 Save
Question list x/, Question 1 */s Question 2 Question 3 Question 4 Question 5 Question 6 Question 7
The production of wine is a multibilion-dollar worldwide industry, In an attempt to develop a model of wine quality as judged by wine experts, data was collected from red wine variants of a certain type of wine. A sample of 12 wines is given. Develop a simple linear regression model to predict wine quality, measured on a scale from 0 (very bad) to 10 (excellent), based on alcohol content (\%) Complete parts (a) through (d) below 囲 Click the icon to view the data of wine quality and alcohol content. a. Construct a scatter plot Choose the correct graph below. b. For these data, $b_{0}=50$ and $b_{1}=0.2$ Interpret the meaning of the slope, $b_{1}$ , in this problem Choose the correct answer below A. The slope, $b_{1}$ , implies that for each increase of alcohol percentage of 10 , the wine quality rating is expected to increase by the value of $b_{1}$
O B. The slope, $\mathrm{b}_{1}$ , implies that for each 0.2 percentage decrease in alcohol content, the wine should have an increase in its rating by 1 . $O C$ . The slope, $\mathrm{b}_{1}$ , implies that the alcohol content is equal to the value of $b_{1}$ , in percentages. O. The slope, $b_{1}$ , implies that for each increase of 1 wine quality rating, the alcohol content is expected to increase by the value of $b_{1}$ , in percentages. c. Predict the mean wine quality for wines with an $12 \%$ alcohol content (Round to two decimal places as needed) solve this View an example Get more help - Clear all Check answer

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Problem 531

Find the confidence interval for the true mean SAT score given a mean of 482 and a margin of error of 15.

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Problem 532

Which of these is a statistical question? A. Lunch period length? B. Oldest student age? C. Classrooms count? D. Ages of classmates?

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Problem 533

Suppose a geologist believes that the average chloride concentration in her local water supply is above the national average of 156 ppm . The geologist defines a null hypothesis, $H_{0}: \mu=156 \mathrm{ppm}$ , to reflect the mean chloride concentration in the national water supply. She formulates an alternative hypothesis, $H_{1}: \mu>156 \mathrm{ppm}$ , to indicate that her locality has a higher concentration of chloride in its water supply, on average. In these hypotheses, $\mu$ represents the true mean concentration of chloride in the local water supply. The geologist samples groundwater from across her locality and determines that the average concentration of chloride in her sample is 208 ppm , with a standard deviation of 35 ppm . Experience has shown that these data can be treated as random samples from a normal population. The geologist uses a one-sample, right-tailed $t$ -test for a mean to test her hypotheses. She computes a $t$ -statistic with a value of 7.862 and 27 degrees of freedom.
Decide the outcome of the geologist's test using a significance level of $\alpha=0.05$ . Fail to reject the null hypothesis because the $P$ -value is greater than $\alpha$ . Reject the null hypothesis because the $P$ -value is greater than $\alpha$ .

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Problem 534

Social networking: Facebook reports that the mean number of friends of adult Facebook users is 338. A test is made of $H_{0}: \mu=338$ versus $H_{1}: \mu<338$ . The null hypothesis is not rejected. State an appropriate conclusion.
There (Choose one) $\nabla$ enough evidence to conclude that the mean number of friends is (Choose one) $\nabla 338$ .

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Problem 535

Content Khulood Ald... Time Remaining: 2434.56 $=1$ 3 $=5$ 8 $=7$ $=6$ 9 10 Khulood Espanat
Recovering from surgery: A new postsurgical treatment was compared with a standard treatment. Ten subjects received the new treatment, while ten others (the controls) received the standard treatment. The recovery times, in days, are given below. \begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|} \hline Treatment: & 11 & 12 & 14 & 16 & 17 & 19 & 20 & 21 & 22 & 26 \\ \hline Control: & 15 & 16 & 17 & 19 & 23 & 24 & 25 & 26 & 27 & 28 \\ \hline \end{tabular}
Send data to Excel
Can you conclude that the mean recovery time for those receiving the new treatment is less than the mean for those receiving the standard treatment? Let $\mu_{1}$ denote the mean recovery time for the new treatment. Use the $\alpha=0.10$ level of significance and the TI-84 Plus calculator.
Part: 0 / 4
Part 1 of 4
State the null and alternate hypotheses. $H_{0}$ : $\square$ $H_{1}$ : $\square$
$\square$
$\mu_{1}$ $\mu_{2}$
The hypothesis test is a (Choose one) $\nabla$ test. $\square$

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Problem 536

WWw-awu.aleks.com Session Clos... Find Your Ma. Quñ Content ExAM Unit 3 Question 8 of 10 (1 poind) \& evestion Altempte 1 of 1 Himotromalhing:283000 Khutiond Ald. $=1$ $=2$ $=3$ 4 $=5$ 7 9 10 Khulewd
Recovering from surgery: A new postsurgical treatment was compared with a standard treatment. Ten subjects received the new treatment, while ten others (the controls) received the standard treatment. The recovery times, in days, are given below. \begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|} \hline Treatment: & 11 & 12 & 14 & 16 & 17 & 19 & 20 & 21 & 22 & 26 \\ \hline Control: & 15 & 16 & 17 & 19 & 23 & 24 & 25 & 26 & 27 & 28 \\ \hline \end{tabular}
Send data to Excel
Can you conclude that the mean recovery time for those receiving the new treatment is less than the mean for those receiving the standard treatment? Let $\mu_{1}$ denote the mean recovery time for the new treatment. Use the $\alpha=0.10$ level of significance and the TI- 84 Plus calculator.
Part: $0 / 4$
Part 1 of 4
State the null and alternate hypotheses. $\begin{array}{l} H_{0}: \mu_{1}=\mu_{2} \\ H_{1}: \mu_{1}<\mu_{2} \end{array}$ Expanet $=8$ (I)

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Problem 537

Carbon monoxide: A recent study examined the effects of carbon monoxide exposure on a group of construction workers. The following table presents the numbers of workers who reported various symptoms, along with the shift (morning, evening, or night) that they worked. \begin{tabular}{cccc} \hline & Morning Shift & Evening Shift & Night Shift \\ \cline { 2 - 4 } Influenza & 17 & 10 & 18 \\ Headache & 32 & 27 & 6 \\ Weakness & 11 & 18 & 9 \\ Shortness of Breath & 4 & 7 & 10 \\ \hline \end{tabular} Send data to Excel
Test the hypothesis of independence. Can you conclude that symptoms and shift are not independent? Use the $\alpha=0.10$ level of significance and the $P$ -value method with the TI-84 Plus calculator.
Part: $0 / 7$
Part 1 of 7 (a) State the null and alternate hypotheses. $H_{0}$ : The shift and reported symptoms (Choose one) $\boldsymbol{\nabla}$ independent. $H_{1}$ : The shift and reported symptoms (Choose one) $\boldsymbol{\nabla}$ independent.

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Problem 538

In a sample of 290 adults, 261 had children. Construct a $95 \%$ confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places $<p<$

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Problem 539

You are studying hypnotherapy's affect on sleep. You measure the hours of sleep for 10 individuals who follow hypnotherapy techniques and get the following results. \begin{tabular}{|r|r|r|} \hline 7.8 & 9 & 9.8 \\ \hline 8.9 & 8.4 & 9.6 \\ \hline 9 & 7.7 & 7.9 \\ \hline 8 & & \\ \hline \end{tabular} a. Find a 99\% confidence interval for the data (Round to 1 decimal place) $\square$ $\square$ ) b. Find the point estimate $\bar{x}=$ $\square$ hours (round to 2 decimals) c. Interpret the confidence interval The average sleeptime for a person who uses hypnotherapy is 8.61 hours $99 \%$ of the time We are $99 \%$ confident that the mean sleep time for people who use hypotherapy is between 7.8 and 9.4 hours We can be $99 \%$ confident that the mean sleep time for people who use hypontherapy is 8.61

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Problem 540

Question 33 A sample of 30 incoming students was taken and whether or not they are left-handed was recorded. A $95 \%$ confidence interval for $p$ is $(9.5 \%, 11.1 \%)$ . a.) The individual object in the study was a randomly selected $\square$ .
This is computer-graded so use exact wording from the problem above. Remember an individual is ONE of something. b.) What was the variable information recorded for each object in the study?
This is computer-graded so use exact wording from the problem above. The variable information was whether or not they $\square$ c.) State the statistical interpretation of the confidence interval in the context of this problem.
Select an answer the $\square$ Select an answer of $\square$ $?$ incoming students that are left-handed is between $\square$ \% and $\square$ \% d.) What is the symbol and value of the point estimate for $p$ ? $?+=$ $\square$ \% e.) What is the margin of error for the given interval? $\qquad$ \% f.) Fill in the boxes below to show the relation on the number line between the numeric values of the point estimate and the interval estimate for $p$ . $\qquad$ $\qquad$ B $\qquad$ $A=$ $\square$ \% B = $\square$ \% C = $\square$ \%

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Problem 541

lecorlan parnal davi data berikart, pada $\alpha=0,01$ dan $\alpha=$ Tabel 1. Data Korlari Rasial \begin{tabular}{|c|c|c|c|} \hline $x_{1}$ & $x_{2}$ & $x_{3}$ & $y$ \\ \hline 4 & 5 & 8 & 7 \\ \hline 7 & 6 & 7 & 9 \\ \hline 7 & 8 & 9 & 12 \\ \hline 6 & 12 & 10 & 8 \\ \hline \end{tabular}

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Problem 542

806 Rati Poor 51 74 57 29 19 37 Test the hypothesis, at 5% level of significance, that rating is not related to age group. 400 120 140 140 TASK 4 A clinical psychologist wishes to compare three methods for reducing hostility levels in university students. A certain psychological test called hostility level test (HLT) was used to measure the degree of hostility. High scores on this test were taken to indicate high hostility. A total of eleven students were tested; five students were selected at random from among the eleven problem cases and treated by method A. From the remaining 6, three were taken at random and treated by method 18 B. The other three students were treated by method C as indicated in following table: SCORES ON THE HLT TEST Method A 73 83 76 68 80 Method B 54 74 71 Method C 79 95 87 (a) Perform an analysis of variance for this experiment. 133 2 85 133×120 182x140. 85 x 140 (b) Do the data provide sufficient evidence to indicate a difference in mean student response for the three methods after treatment? DUE: FRIDAY 23RD AUGUST, 2024 BEFORE 17:00HRS KASHOKA.B UNZA KACE 21 Page 2 450

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Problem 543

At a water bottling factory, a machine is supposed to put 2 liters of water into the bottles. After an overhaul, management thinks the machine is no longer putting the correct amount of water in. They sample 20 bottles and and find an avg of 2.10 L of water with standard deviation of 0.33 L . Test the claim at 0.01 level of significance.

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Problem 544

I Karasjok ble det de sju siste dagene i 2022 målt følgende temperaturer kl 12 om formiddagen: $-24.7^{\circ} \mathrm{C},-8.4^{\circ} \mathrm{C},-5.6^{\circ} \mathrm{C},-8.1^{\circ} \mathrm{C},-26.2^{\circ} \mathrm{C},-6.7^{\circ} \mathrm{C},-3.0^{\circ} \mathrm{C}$ .
Gjennomsnittstemperaturen over de ti siste årene i Karasjok den siste uka i desember er $-12.1^{\circ} \mathrm{C}$ . Vi skal nå unders $\varnothing$ ke om gjennomsnittstemperaturen siste uka i 2022 har vært signifikant forskjellig fra tidligere år. b: Sett opp en nullhypotese og en alternativ hypotese. Forklar hvorfor du har valgt de to hypotesene og hva slags hypotesetest du mener er riktig å benytte i dette tilfellet.

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Problem 545

Money Arguments A survey found that one in five couples often argue about money. A random sample of 200 couples found that 36 couples said that they often argued about money. Is there significant evidence at the 0.05 level to conclude that the proportion is less than one in five couples? Use the critical value method. Do not round intermediate steps.
Part: $0 / 5$
Part 1 of 5 (a) State the hypotheses and identify the claim. $\begin{array}{l} H_{0}: \square(\text { Choose one } \nabla \\ H_{1}: \square(\text { Choose one } \nabla \end{array}$
This hypothesis test is a (Choose one) $\nabla$ test. $\square$

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Problem 546

The driving distance was recorded for each Harper student in a sample of 30 . A $95 \%$ confidence interval for $\mu$ is $(12,24)$ miles. a) The individual object in the study was a randomly selected $\qquad$ This is computer-graded so use exact wording from the problem above. $\square$ b) What was the variable information recorded for each object in the study?
This is computer-graded so use exact wording from the problem above. $\square$ c) State the statistical interpretation of the confidence interval in the context of this problem. - Select an answer $\qquad$ the $\square$ driving distance of $\square$ ? Harper students is/are between $\square$ $\square$ and $\square$ $\square$ d) What is the symbol and value of the point estimate for $\mu$ ? $\square$ $? \quad 0=$ miles e) What is the margin of error for the given interval? $\square$ miles f) Fill in the boxes below to show the relation on the number line between the numeric values of the point estimate and the interval estimate for $\mu$ . $A=\square B=\square C=\square$

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Problem 547

An epidemiologist plans to conduct a survey to estimate the percentage of women who give birth. How many women must be surveyed in order to be $95 \%$ confident that the estimated percentage is in error by no more than one percentage point? Complete parts (a) through (c) below. a. Assume that nothing is known about the percentage to be estimated. $\mathrm{n}=\square$ (Round up to the nearest integer.) b. Assume that a prior study conducted by an organization showed that $81 \%$ of women give birth. $n=$ $\square$ (Round up to the nearest integer.) c. What is wrong with surveying randomly selected adult women? A. Randomly selecting adult women would result in an overestimate, because some women will give birth to their first child after the survey was conducted. It will be important to survey women who have completed the time during which they can give birth. B. Randomly selecting adult women would result in an overestimate, because some women will give birth to their first child after the survey was conducted. It will be important to survey women who have already given birth. C. Randomly selecting adult women would result in an underestimate, because some women will give birth to their first child after the survey was conducted. It will be important to survey women who have already given birth. D. Randomly selecting adult women would result in an underestimate, because some women will give birth to their first child after the survey was conducted. It will be important to survey women who have completed the time during which they can give birth.

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Problem 548

An IQ test is designed so that the mean is 100 and the standard deviation is 10 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with $95 \%$ confidence that the sample mean is within 8 IQ points of the true mean. Assume that $\sigma=10$ and determine the required sample size using technology. Then determine if this is a reasonable sample size for a real world calculation.
The required sample size is $\square$ (Round up to the nearest integer.)
Would it be reasonable to sample this number of students? No. This number of $I Q$ test scores is a fairly small number. No. This number of IQ test scores is a fairly large number. Yes. This number of IQ test scores is a fairly large number. Yes. This number of IQ test scores is a fairly small number.

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Problem 549

A college entrance exam company determined that a score of 20 on the mathematics portion of the exam suggests that a student is ready for college-level mathematics. To achieve this goal, the company recommends that students take a core curriculum of math courses in high school. Suppose a random sample of 150 students who completed this core set of courses results in a mean math score of 20.3 on the college entrance exam with a standard deviation of 3.1. Do these results suggest that students who complete the core curriculum are ready for college-level mathematics? That is, are they scoring above 20 on the mathematics portion of the exam? Complete parts a) through d) below.
Click the icon to view the table of critical $t$ -values. (a) State the appropriate null and alternative hypotheses. Fill in the correct answers below.
The appropriate null and alternative hypotheses are $\mathrm{H}_{0}$ : (Type integers or decimals. Do not round.) $\square$ 20 versus $\mathrm{H}_{1}$ : $\square$ 20. (b) Verify that the requirements to perform the test using the $t$ -distribution are satisfied. Select all that apply. A. The sample data come from a population that is approximately normal. B. The sample size is larger than 30 . C. The students were randomly sampled. D. The students' test scores were independent of one another. E. A boxplot of the sample data shows no outliers. F. None of the requirements are satisfied.

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Problem 550

Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 26 g equals about 12 chips. That means, on average, each chip should weigh 2.17 g . Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample $t$ -test with a significance level of $\alpha=0.05$ to test the null hypothesis, $H_{0}: \mu=2.17$ , against the alternative hypothesis, $H_{1}: \mu \neq 2.17$ , where $\mu$ is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. \begin{tabular}{ccccc} Sample size & Sample mean & Sample standard deviation & Test statistic & Probability value \\ \hline $n$ & $\bar{x}$ & $s$ & $t$ & $P$ -value \\ 50 & 2.19 & 0.11 & 1.500 & 0.140 \end{tabular}
Based on these results, complete the following sentences to state the decision and conclusion of the test.
Matilde's decision is to $\qquad$ the $\qquad$ ( $P=0.140$ ). There is $\qquad$ evidence to $\square$ the claim that the average weight

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Problem 551

Question 5, 11.1.13-SC HW Score: 5 Points:
Construct a confidence interval for $p_{1}-p_{2}$ at the given level of confidence. $x_{1}=388, n_{1}=504, x_{2}=449, n_{2}=586,99 \% \text { confidence }$
The confidence interval is ( $\square$ , $\square$ ). (Round to three decimal places as needed.)

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Problem 552

Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6178 patients treated with this drug, 155 developed the adverse reaction of nausea. Use a 0.01 significance level to test the claim that $3 \%$ of users develop nausea. Does nausea appear to be a problematic adverse reaction?
Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. $\mathrm{H}_{0}: p=0.03$ $H_{1}: p \neq 0.03$ B. $H_{0}: p=0.03$ $H_{1}: p<0.03$ C. $H_{0}: p=0.03$ $H_{1}: p>0.03$ D. $H_{0}: p \neq 0.03$ $H_{1}: p=0.03$ Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is $\square$ . (Round to two decimal places as needed.)

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Problem 553

You are conducting a hypothesis test at the 0.05 alpha level for the claim that a die is fair. In other words, all sides of the die are equally likely when rolled. The table below shows how the die landed after many rolls. \begin{tabular}{|l|l|} \hline \begin{tabular}{l} Category \\ How die \\ landed \end{tabular} & \begin{tabular}{l} Observed \\ Frequency \end{tabular} \\ \hline 1 & 9 \\ \hline 2 & 5 \\ \hline 3 & 6 \\ \hline 4 & 15 \\ \hline 5 & 22 \\ \hline 6 & 7 \\ \hline \end{tabular}
Report all answers accurate to two decimal places. What is the chi-square test-statistic for this data? $\chi^{2}=20.36$

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Problem 554

Question 7 $0 / 1$ pt 5 99 Details
You intend to conduct a test of independence for a contingency table with 6 categories in the column variable and 6 categories in the row variable. You collect data from 654 subjects.
What are the degrees of freedom for the $\chi^{2}$ distribution for this test? d.f. = $\square$ Question Help: Written Example
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Problem 555

You are conducting a test of the claim that the color of the case of your cell phone is dependent on your gender. \begin{tabular}{|c||c|c|c|} \hline & Black & White & Blue \\ \hline Male & 80 & 88 & 51 \\ \hline Female & 56 & 14 & 94 \\ \hline \hline \end{tabular}
Give all answers rounded to 2 places after the decimal point, if necessary. (a) What is the chi-square test-statistic for this data?
Test Statistic: $\chi^{2}=$ $\square$ (b) What is the critical value for this test of independence when using a significance level of $\alpha=0.05$ ? Critical Value: $\chi^{2}=$ $\square$ (c) What is the correct summary of this hypothesis test at the 0.05 significance level? I was unable to show that your choice of color is dependent on your gender. I was able to show that your choice of color is independent of your gender. I was unable to show that your choice of color is independent of your gender. I was able to show that your choice of color is dependent on your gender. Question Help: Fig Written Example
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Problem 556

$\rightleftarrows$ Get a similar question You can retry this question below
You are conducting a test of the claim that the color of the case of your cell phone is dependent on your gender. \begin{tabular}{|c|c|c|c|c|} \hline & Black & White & Blue \\ \hline Male & 80 & 88 & 51 \\ \hline Female & 56 & 14 & 94 \\ \hline \end{tabular}
Give all answers rounded to 2 places after the decimal point, if necessary. (a) What is the chi-square test-statistic for this data?
Test Statistic: $\chi^{2}=63.18 \quad$ x (b) What is the critical value for this test of independence when using a significance level of $\alpha=0.05$ ? critical value: $\chi^{2}=5.99$ (c) What is the correct summary of this hypothesis test at the 0.05 significance level? I was unable to show that your choice of color is dependent on your gender. I was able to show that your choice of color is independent of your gender. I was unable to show that your choice of color is independent of your gender. I was able to show that your choice of color is dependent on your gender.

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Problem 557

Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund medical research using stem cells obtained from human embryos." Of those polled, 489 were in favor, 398 were opposed, and 122 were unsure. A politician claims that people don't really understand the stem cell issue and their responses to such questions are random responses equivalent to a coin toss. Exclude the 122 subjects who said that they were unsure, and use a 0.10 significance level to test the claim that the proportion of subjects who respond in favor is equal to 0.5 . What does the result suggest about the politician's claim? A. $\mathrm{H}_{0}: p=0.5$ $H_{1}: p<0.5$ B. $H_{0}: p=0.5$ $H_{1}: p \neq 0.5$ C. $\begin{array}{l} H_{0}: p=0.5 \\ H_{1}: p>0.5 \end{array}$ D. $\begin{array}{l} H_{0}: p \neq 0.5 \\ H_{1}: p=0.5 \end{array}$
Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is 3.04 . (Round to two decimal places as needed.) Identify the P -value for this hypothesis test. The P-value for this hypothesis test is $\square$ (Round to three decimal places as needed.)

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Problem 558

Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund medical research using stem cells obtained from human embryos." Of those polled, 489 were in favor, 398 were opposed, and 122 were unsure. A politician claims that people don't really understand the stem cell issue and their responses to such questions are random responses equivalent to a coin toss. Exclude the 122 subjects who said that they were unsure, and use a 0.10 significance level to test the claim that the proportion of subjects who respond in favor is equal to 0.5 . What does the result suggest about the politician's claim?
The test statistic for this hypothesis test is 3.04 (Round to two decimal places as needed.) Identify the P -value for this hypothesis test. The P-value for this hypothesis test is 0.002 . (Round to three decimal places as needed.) Identify the conclusion for this hyporitesis test. A. Fail to reject $\mathrm{H}_{0}$ . There is not sufficient evidence to warrant rejection of the claim that the responses are equivalent to a coin toss. B. Fail to reject $\mathrm{H}_{0}$ . There is sufficient evidence to warrant rejection of the claim that the responses are equivalent to a coin toss. C. Reject $\mathrm{H}_{0}$ . There is not sufficient evidence to warrant rejection of the claim that the responses are equivalent to a coin toss. D. Reject $\mathrm{H}_{0}$ . There is sufficient evidence to warrant rejection of the claim that the responses are equivalent to a coin toss.

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Problem 559

Suppose that in a random selection of 100 colored candies, $26 \%$ of them are blue. The candy company claims that the percentage of blue candies is equal to $27 \%$ . Use a 0.05 significance level to test that claim.
Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. $\mathrm{H}_{0}: \mathrm{p}=0.27$ $H_{1}: p<0.27$ B. $H_{0}: p \neq 0.27$ $H_{1}: p=0.27$ C. $H_{0}: p=0.27$ $H_{1}: p \neq 0.27$ D. $\begin{array}{l} H_{0}: p=0.27 \\ H_{1}: p>0.27 \end{array}$
Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is $\square$ $\square$ . (Round to two decimal places as needed.)

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Problem 560

Suppose 234 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.01 significance level to test the claim that more than $20 \%$ of users develop nausea.
Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. $H_{0}: p=0.20$ $H_{1}: p>0.20$ B. $H_{0}: p>0.20$ $H_{1}: p=0.20$ c. $H_{0}: P=0.20$ $\mathrm{H}_{1}: \mathrm{p}<0.20$ D. $H_{0}: p=0.20$ $H_{1}: p \neq 0.20$
Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is $\square$ $\square$ . (Round to two decimal places as needed.).

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Problem 561

Part 4 of 8 HW Score:
Assume that the differences for the given data are normally distributed. Complete parts (a) through (d). Click here to view the sample data. Click here to view the table of critical t-values. Points: (a) Determine $d_{i}=X_{i}-Y_{i}$ for each pair of data. \begin{tabular}{|l|c|c|c|c|c|c|c|} \hline Observation & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline $\mathbf{d}_{\mathbf{i}}$ & -0.5 & 1.1 & -3.3 & -3.8 & 0.5 & -2.3 & -2.9 \\ \hline \end{tabular} (b) Compute $\overline{\mathrm{d}}$ and $\mathrm{s}_{\mathrm{d}}$ . $\overline{\mathrm{d}}=-1.600$ (Round to three decimal places as needed.) $s_{d}=1.950$ (Round to three decimal places as needed.) (c) Test if $\mu_{\mathrm{d}}<0$ at the $\alpha=0.05$ level of significance.
Determine the null and alternative hypotheses. Choose the correct answer. A. $H_{0}: \mu_{d}=0$ $\mathrm{H}_{1}: \mu_{\mathrm{d}}<0$ B. $H_{0}: \mu_{d}<0$ C. $H_{0}: \mu_{d}>0$ $\mathrm{H}_{1}: \mu_{\mathrm{d}}=0$ $H_{1}: \mu_{d}<0$ D. $H_{0}: \mu_{d}<0$ $\mathrm{H}_{1}: \mu_{\mathrm{d}}>0$

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Problem 562

Part 5 of 8 HW Score: $12.5 \%, 1$ of 8 points O Points: 0 of 1
Assume that the differences for the given data are normally distributed. Complete parts (a) through (d). Click here to view the sample data. Click here to view the table of critical t-values. Points: 0 of 1 $\qquad$ (a) Determine $d_{i}=X_{i}-Y_{i}$ for each pair of data. \begin{tabular}{|l|c|c|c|c|c|c|c|} \hline Observation & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline $\mathbf{d}_{\mathbf{i}}$ & -0.5 & 1.1 & -3.3 & -3.8 & 0.5 & -2.3 & -2.9 \\ \hline \end{tabular} (b) Compute $\overline{\mathrm{d}}$ and $\mathrm{s}_{\mathrm{d}}$ . $\overline{\mathrm{d}}=-1.600$ (Round to three decimal places as needed.) $\mathrm{s}_{\mathrm{d}}=1.950$ (Round to three decimal places as needed.) (c) Test if $\mu_{d}<0$ at the $\alpha=0.05$ level of significance.
Determine the null and alternative hypotheses. Choose the correct answer. A. $H_{0}: \mu_{d}=0$ $\mathrm{H}_{1}: \mu_{\mathrm{d}}<0$ B. $H_{0}: \mu_{d}<0$ $H_{1}: \mu_{d}=0$ C. $H_{0}: \mu_{d}>0$ $\mathrm{H}_{1}: \mu_{d}<0$ D. $H_{0}: \mu_{d}<0$ $H_{1}: \mu_{d}>0$ Determine the test statistic. The test statistic is $\square$ (Round to two decimal places as needed.)

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Problem 563

When Brett Kavanaugh was nominated to be a Supreme Court justice, a survey of 1002 Americans showed that $50.9 \%$ of them disapproved of Kavanaugh. A newspaper published an article with this headline: "Majority of Americans Disapprove of Kavanaugh." Use a 0.10 significance level to test the claim made in that headline. Use the P -value method. Use the normal distribution as an approximation to the binomial distribution.
Let $p$ denote the population proportion of all Americans who disapproved of Kavanaugh. Identify the null and alternative hypotheses. $\begin{array}{l|l|l} \mathrm{H}_{0}: \mathrm{p} & \mathrm{~V} & \square \\ \mathrm{H}_{1}: \mathrm{p} & \mathrm{~V} & \square \end{array}$ (Type integers or decimals. Do not round.)

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Problem 564

Tiffany Poynter $\quad 11 / 24 / 24$ 5:46 PM ing a Claim about a Question 10, 8.2.26-T HW Score: 48.56\%, 8.26 of 17 points Test)
Part 2 of 4 Points: 0.22 of 1 Save
When Brett Kavanaugh was nominated to be a Supreme Court justice, a survey of 1002 Americans showed that $50.9 \%$ of them disapproved of Kavanaugh. A newspaper published an article with this headline: "Majority of Americans Disapprove of Kavanaugh." Use a 0.10 significance level to test the claim made in that headline. Use the P -value method. Use the normal distribution as an approximation to the binomial distribution.
Let p denote the population proportion of all Americans who disapproved of Kavanaugh. Identify the null and alternative hypotheses. $\begin{array}{l} H_{0}: p=0.5 \\ H_{1}: p>0.5 \end{array}$ (Type integers or decimals. Do not round.) Identify the test statistic. $\mathbf{z}=\square$ (Round to two decimal places as needed.)

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Problem 565

Assume that the differences for the given data are normally distributed. Complete parts (a) through (d). Click here to view the sample data. Click here to view the table of critical t-values. A. $H_{0}: \mu_{d}=0$ $H_{1}: \mu_{d}<0$
Sample Data C. $H_{0}: \mu_{d}>0$ $H_{1}: \mu_{d}<0$
Determine the test statistic. \begin{tabular}{|llccccccc|} \hline & Observation & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline $\boldsymbol{X}_{\mathbf{i}}$ & 7.7 & 7.6 & 7.4 & 5.7 & 8.3 & 6.6 & 5.7 \\ \hline $Y_{i}$ & 8.2 & 6.5 & 10.7 & 9.5 & 7.8 & 8.9 & 8.6 \\ \hline \end{tabular}
The test statistic is -2.17 . (Round to two decimal places as needed.) Determine the critical value(s). Print Done
The critical value(s) is/are -1.94 . (Round to two decimal places as needed. Use a comma to separate Determine the proper conclusion. Reject $\square$ the null hypothesis. There is $\square$ sufficient evidence that $\mu_{\mathrm{d}}$ $\square$ 0 at the $\alpha=0.05$ level of significance. (d) Construct a 95\% confidence interval about the population mean difference $\mu_{\mathrm{d}}$ .
The lower bound is $\square$ The upper bound is $\square$ (Round to two decimal places as needed.)

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Problem 566

It is believed that $11 \%$ of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 310 students from that college, whether or not a student was left-handed was recorded for each student. The college wants to know if the data provide enough evidence to show that students at this college have a different percentage of left-handers than the general American population? State the random yariable, population parameter, and hypotheses. State the Type I and Type II errors in the context of this problem. a) The symbol for the random variable involved in this problem is ?
The wording for the random variable in context is as follows: Select an answer b) The symbol for the parameter involved in this problem is $\square$ ? 0
The wording for the parameter in context is as follows: Select an answer c) Fill in the correct null and alternative hypotheses: $\begin{array}{l} H_{0} \text { : ? 주웅 } \\ H_{A}: \text { ? ? } \end{array}$ d) A Type I error in the context of this problem would be: $\checkmark$ Select an answer Rejecting that the \% of all students from that college that are left-handed is $11 \%$ when the $\%$ is really $11 \%$ . Rejecting that the \% of all students from that college that are left-handed is $11 \%$ when the $\%$ is really lower than that. Rejecting that the $\%$ of all students from that college that are left-handed is $11 \%$ when the $\%$ is really higher than that. Rejecting that the $\%$ of all students from that college that are left-handed is $11 \%$ when the $\%$ is really different from that. Rejecting that the \% of all students from that college that are left-handed is lower than $11 \%$ when the \% is really $11 \%$ . Rejecting that the $\%$ of all students from that college that are left-handed is higher than $11 \%$ when the \% is really $11 \%$ . Rejecting that the \% of all students from that college that are left-handed is different from $11 \%$ when the \% is really $11 \%$ . Failing to reject that the $\%$ of all students from that college that are left-handed is $11 \%$ when the $\%$ is really $11 \%$ . Failing to reject that the $\%$ of all students from that college that are left-handed is $11 \%$ when the $\%$ is really lower than that. Failing to reject that the $\%$ of all students from that college that are left-handed is $11 \%$ when the $\%$ is really higher than that.

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Problem 567

According to the Federal Trade Commission report on consumer fraud and identity theft, $23 \%$ of all complaints in 2007 were for identity theft. This year, a certain state kept track of how many of its 1300 complaints were for identity theft. They want to know if the data provide enough evidence to show that this state had a higher proportion of identity theft than $23 \%$ ? State the random variable, population parameter, and hypotheses. a) The symbol for the random variable involved in this problem is ? $\square$ The wording for the random variable in context is as follows: Select an answer b) The symbol for the parameter involved in this problem is ? 0
The wording for the parameter in context is as follows: Select an answer c) Fill in the correct null and alternative hypotheses: $H_{0}$ : $\square$ ? $\square$ $H_{A}$ : ? $\square$ ? $\square$

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Problem 568

A recent broadcast of a television show had a 10 share, meaning that among 6000 monitored households with TV sets in use, 10\% of them were tuned to this program. Use a 0.01 significance level to test the claim of an advertiser that among the households with TV sets in use, less than 20\% were tuned into the program. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P -value method. Use the normal distribution as an approximation of the binomial distribution.
Identify the null and alternative hypotheses. Choose the correct answer below. A. $H_{0}: p=0.80$ B. $H_{0}: p=0.80$ $H_{1}: p<0.80$ $H_{1}: p>0.80$ C. $H_{0}: p=0.20$ D. $H_{0}: p=0.20$ $H_{1}: p \neq 0.20$ $H_{1}: p<0.20$ E. $H_{0}: p=0.80$ F. $H_{0}: p=0.20$ $H_{1}: p \neq 0.80$ $H_{1}: p>0.20$
The test statistic is $\mathrm{z}=$ $\square$ . (Round to two decimal places as needed.) Clear all Check answer Help me solve this Get more help -

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Problem 569

Does the average Presbyterian donate more than the average Catholic in church on Sundays? The 58 randomly observed members of the Presbyterian church donated an average of $\$ 27$ with a standard deviation of \ $13. The 55 randomly observed members of the Catholic church donated an average of \$26 with a standard deviation of$ \ $7$ . What can be concluded at the $\alpha=0.10$ level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: $H_{0}$ : Select an answer Select an answer Select an answer (2) (please enter a decimal) $H_{1}$ : Select an answer Select an answer Select an answer (Please enter a decimal) c. The test statistic ? : = $\square$ (please show your answer to 3 decimal places.) d. The $p$ -value $=$ $\square$ (Please show your answer to 4 decimal places.) e. The $p$ -value is ? $\alpha$ f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The results are statistically significant at $\alpha=0.10$ , so there is sufficient evidence to conclude that the mean donation for the 58 Presbyterians that were observed is more than the mean donation for the 55 Catholics that were observed. The results are statistically significant at $\alpha=0.10$ , so there is sufficient evidence to conclude that the population mean amount of money that Presbyterians donate is more than the population mean amount of money that Catholics donate. The results are statistically insignificant at $\alpha=0.10$ , so there is insufficient evidence to conclude that the population mean amount of money that Presbyterians donate is more than the population mean amount of money that Catholics donate. The results are statistically insignificant at $\alpha=0.10$ , so there is statistically significant evidence to conclude that the population mean amount of money that Presbyterians donate is equal to the population mean amount of money that Catholics donate.

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Problem 570

Question 3, 11.2.3-T Part 5 of 7 HW Score: $30.2 \%, 2.42$ of 8 point Points: 0.53 of 1
Assume that the differences are normally distributed. Complete parts (a) through (d) below. \begin{tabular}{lcccccccc} Observation & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ $\mathrm{X}_{\mathrm{i}}$ & 51.0 & 51.3 & 49.0 & 45.1 & 47.8 & 43.0 & 44.1 & 47.1 \\ $\mathrm{Y}_{\mathrm{i}}$ & 53.7 & 49.8 & 54.1 & 48.9 & 46.9 & 45.5 & 46.3 & 49.8 \end{tabular} (a) Determine $d_{i}=X_{i}-Y_{i}$ for each pair of data. \begin{tabular}{l|c|c|c|c|c|c|c} \hline Observation & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline $\mathbf{d}_{\mathbf{i}}$ & -2.7 & 1.5 & -5.1 & -3.8 & 0.9 & -2.5 & -2.2 \\ \hline & -2.7 \\ \hline \end{tabular} (Type integers or decimals.) (b) Compute $\overline{\mathrm{d}}$ and $\mathrm{s}_{\mathrm{d}}$ . $\overline{\mathrm{d}}=-2.075$ (Round to three decimal places as needed.) $s_{d}=2.228$ (Round to three decimal places as needed.) (c) Test if $\mu_{\mathrm{d}}<0$ at the $\alpha=0.05$ level of significance.
What are the correct null and alternative hypotheses? A. $H_{0}: \mu_{d}=0$ B. $H_{0}: \mu_{d}<0$ $H_{1}: \mu_{d}<0$ $\mathrm{H}_{1}: \mu_{\mathrm{d}}=0$ C. $H_{0}: \mu_{d}>0$ D. $H_{0}: \mu_{d}<0$ $H_{1}: \mu_{d}<0$ $\mathrm{H}_{1}: \mu_{\mathrm{d}}>0$
P -value $=$ $\square$ (Round to three decimal places as needed.)

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Problem 571

ing a Claim about a Question 20, Question HW Score: 27.58\%, 5.19 of 21 points Points: 0 of 1 Save
This is the second problem where we want you to use the tcdf calculator program to find a p-value when you already have the Test Statistic. If you have not already accessed it, you need to open the Technology Guide to find P-values (with Examples) Handout found in Content for detailed steps and examples. There is also a video that works through examples of these. Follow the directions for a right tailed test for this problem provided on the handout. The bounds you need to enter in your calculator for a right tailed test are specified on the handout. Do not guess. Read and follow the directions. Use Technology to find the p -value for the claim H1: $\mu>44.6$ , if the test statistic is known to be $\mathrm{t}=1.67$ and $\mathrm{n}=151$ . Will the test statistic, $\mathrm{t}=\mathbf{1 . 6 7}$ , be the upper or lower bound for a right tail test? A. Lower bound, since we want the area to the right of this value for a right tail. B. Upper bound, since we want the area to the left of this value for a right tail.
What is the p-value? $\square$ Round your answer to 4 decimal places. Clear all Check answer

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Problem 572

Over 8-2 \& 8-3) Question 3 or 12 This questioni:
Suppose a principal claims that the mean test score at her school is greater than the national average. She performs a hypothesis test and finds the test statistic to be $t=1.77$ and she knows the critical value for this test to be $t=1.98$ . What can she conclude? A. There is not sufficient evidence to support her claim since the test statistic does not fall in the critical region. B. There is not sufficient evidence to support her claim since the test statistic falls in the critical region. C. There is sufficient evidence to support her claim since the test statistic falls in the critical region. D. There is sufficient evidence to support her claim since the test statistic does not fall in the critical region.

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Problem 573

4 Homework Question 3, 8.4.63 Part 4 of 6 HW Score: 20\%, 2 of 10 points Points: 0 of 1 Save
A study for the treatment of patients with HIV-1 was a randomized, controlled, double-blind study that compared the effectiveness of ritonavir-boosted darunavir (rbd), the drug currently used to treat HIV-1, with dorovirine, a newly developed drug. Of the 376 subjects taking ritonavir-boosted darunavir, 305 achieved a positive result. Of the 376 subjects taking dorovirine, 326 achieved a positive result. Comp parts (a) and (b). D. $\begin{array}{l} H_{0}: p_{1}=p_{2} \\ H_{a}: p_{1}<p_{2} \end{array}$ E. $H_{0}: p_{1}=p_{2}$ $H_{a}: p_{1} \neq p_{2}$ F. $H_{0}: p_{1}>p_{2}$ $H_{a}: p_{1}=p_{2}$
Identify the test statistic. $z=-2.08^{\top}$ (Round to two decimal places as needed.) Identify the p-value. $p$ -value $=$ $\square$ (Round to three decimal places as needed.) example Get more help - Clear all Check an

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Problem 574

Use the shoe print lengths and heights shown below to find the regression equation, letting shoe print lengths be the predictor ( x ) variable. Then find the best predicted height of a male who has a shoe print length of 27.5 cm . Would the result be helpful to police crime scene investigators in trying to describe the male? Use a significance level of $\alpha=0.05$ . \begin{tabular}{|l|r|r|r|r|r|} \hline Shoe Print (cm) & 29.3 & 29.3 & 31.8 & 31.9 & 27.3 \\ \hline Foot Length $(\mathrm{cm})$ & 25.7 & 25.4 & 27.9 & 26.7 & 25.1 \\ \hline Height $(\mathrm{cm})$ & 175.4 & 177.6 & 185.6 & 175.4 & 173.4 \\ \hline \end{tabular}
What is the regression equation? $y=131.8+1.5 x$ (Round to one decimal place as needed.) The best predicted height is $\square \mathrm{cm}$ . (Round to two decimal places as needed.)

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Problem 575

Elise has two loans: a \$20,000 fixed-rate at 4.5\% and a \$20,000 variable-rate at 4.15\%. Which is more predictable in total cost?

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Problem 576

Is the frequency distribution normal based on the criteria? Choose A, B, or C based on the given temperature ranges and frequencies.

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Problem 577

Calculate the correlation coefficient $r$ and the regression line for the given sea level pressure and wind speed data. Then predict wind speed for 977 millibars. Round appropriately.

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Problem 578

Determine the correlation coefficient $r$ , regression line, and predict weight for a 124-inch alligator. Is it valid for 20 inches?

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Problem 579

Tax-Exempt Properties A tax collector wishes to see if the mean values of the tax-exempt propertice are different for two cities. The values of the tax-exempt properties for the two samples are shown. The data are given in millions of bollars. At $\alpha=0.10$ , is there endugh evidence tos support the tax eallector's edaim that the mesus sre different? \begin{tabular}{cccc|cccc} \multicolumn{4}{c|}{ Clty A } & \multicolumn{4}{|c}{ Clty B } \\ \hline 10 & 52 & 13 & 27 & 68 & 11 & 81 & 9 \\ 15 & 31 & 16 & 22 & 82 & 50 & 12 & 4 \\ 33 & 38 & 31 & 39 & 20 & 5 & 15 & 12 \\ 19 & 27 & & & 2 & 5 & 16 & \end{tabular} Sand tata to Ercel
Use $\mu_{i}$ for the mean value of tax-exempt properties in City A. Assume the variables are normally distributed and the variances are unequal.
Port 1 of 5
State the hypotheses and identify the claim with the correct hypothesis. $H_{0}: \mu_{1}=\mu_{2} \quad$ net claim $\quad \boldsymbol{}$ $H_{1}: \mu_{1} \neq \mu_{2} \quad$ dolm This hypothesis test is a two-talled $\quad 7$ test.
Part: $1 / 5$
Part 2 of 5
Find the critical value(s). Round the answer(s) to at least three decimal places. If there more than one citical value, separate them with commas. Critical value(s): $\square$

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Problem 580

A data set includes wait times (minutes) for the Tower of Terror ride at Wall Disney World's Hollywood Studios theme park at 5.00 PM. Using 33 of the times to test the claim that the mean of all such wait times is more than 30 minutes, the accompanying Excel display is obtained. Test the given claim by using the display provided from Excel. Use a 0.05 significance level.
Click the icon to view the Excel display.
Identify the null and allemative hypotheses. $\begin{array}{l} \mathrm{H}_{0}: \mu=30 \\ \mathrm{H}_{1}: \mu>30 \end{array}$ (Type integers or decimals. Do not round.) Identify the test statistic. $\square$ (Round to two decimal places as needed.)
Excel Display \begin{tabular}{|lr|} \hline Difference & 3 \\ \hline $t$ (Observed value) & 1.007 \\ \hline $t$ (Critical value) & 1.694 \\ \hline DF & 32 \\ \hline $p$ -value (one-tailed) & 0.161 \\ \hline alpha & 0.05 \\ \hline \end{tabular} Help me solve this Get more help -

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Problem 581

A fashion company releases a new line of prom dresses that are all under $\$ 100$ . They claim this is a bargain because the average cost of a prom dress is over $\$ 300$ . A customer decide to test this, and takes a random sample of 25 dresses. She finds the mean is $\$ 250$ with a standard deviation of $\$ 10$ . Assume the population is normally distributed and use $\alpha=0.0$ to test the claim.
Which distribution should be used to test the claim? Z-test for the Mean T-test for the Mean p-distribution c-distribution

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Problem 582

asing a calculator or statisucal sortware, rind the innear regression line for the data in the table below. Enter your answer in the form $y=m x+b$ , with $m$ and $b$ both rounded to two decimal places. \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline 1 & 4.59 \\ \hline 2 & 4.99 \\ \hline 3 & 6.74 \\ \hline 4 & 7.72 \\ \hline 5 & 8.92 \\ \hline 6 & 10.17 \\ \hline 7 & 10.37 \\ \hline \end{tabular}
Provide your answer below: $y=\square \mathrm{r}+\square$

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Problem 583

Question 16 4 pts
A sociologist wants to determine if the average household income in a city is greater than the state average of $\$ 50,000$ . She collects data from a random sample of 35 households, and the population standard deviation is unknown.
What type of hypothesis test is appropriate? One-tailed T test for the nean- Two-tailed Z test for the mean Two-tailed T test for the mean One-tailed Z test for the proportion One-tailed Z test for the mean

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Problem 584

ATH-1530-L40 - Introductory Statistics Tiffany Poynter 11/24/24 8:35 PM
Homework: 9-2 Two Means: Independent Samples (2-Samp T-Test) Question 2, 9.2.11-T HW Score: 0\%, 0 of 15 points Save uestion list
Question 2
Question 3
Question 4 Question 5 Question 6
Researchers conducted a study to determine whether magnets are effective in treating back pain. Pain was measured using the visual analog scale, and the results shown below are among the results obtained in the study. Higher scores correspond to greater pain levels. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) to (c) below.
Reduction in Pain Level After Magnet Treatment $\left(\mu_{1}\right): n=24, \bar{x}=0.57, s=0.88$ Reduction in Pain Level After Sham Treatment $\left(\mu_{2}\right): n=24, \bar{x}=0.49, s=1.41$ to a placebo). What are the null and alternative hypotheses? A. $\mathrm{H}_{0}: \mu_{1}=\mu_{2}$ $H_{1}: \mu_{1} \neq \mu_{2}$ B. $H_{0}: \mu_{1}=\mu_{2}$ $H_{1}: \mu_{1}>\mu_{2}$ C. $H_{0}: \mu_{1}<\mu_{2}$ D. $\begin{array}{l} H_{0}: \mu_{1} \neq \mu_{2} \\ H_{1}: \mu_{1}<\mu_{2} \end{array}$
The test statistic, $t$ , is $\square$ (Round to two decimal places as needed.) View instructor tip Help me solve this Get more help - Clear all Check answer Type here to search

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Problem 585

Part 5 of 5 Points: 0.2 of 1 Save
In a study published in a journal, occupational accidents at three construction sites in a country were monitored. The total numbers of accidents at the three randomly selected sites were 51,104 , and 37 . Summary statistics for these three sites are: $\bar{x}=64$ and $s=35.3$ . Suppose an occupational safety inspector claims that the average number of occupational accidents at all of the country's construction sites is less than 70. a. Give the appropnate conciusion tor the test: unoose the correct answer Delow. A. Reject $\mathrm{H}_{0}$ . There is sufficient evidence to indicate that the average number of occupational accidents is less than 70 . B. Do not reject $H_{0}$ . There is sufficient evidence to indicate that the average number of occupational accidents is less than 70 . C. Reject $H_{0}$ . There is insufficient evidence to indicate that the average number of occupational accidents is less than 70 . D. Do not reject $\mathrm{H}_{0}$ . There is insufficient evidence to indicate that the average number of occupational accidents is less than 70 . e. What conditions are required for the test results to be valid? Select all that apply A. The sample was selected from a population with a distribution that is approximately normal. B. The sample was random. C. The population standard deviation is known. D. The sample was selected from a population with a distribution that is highly skewed. E. No assumptions are required for this test. Clear all Check answer 10:01 PM 11/24/2024

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Problem 586

This question: 1 point(s) possible Submit quiz
Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal, Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. \begin{tabular}{|c|c|c|} \hline & Diet & Regular \\ \hline $\mu$ & $\mu_{1}$ & $\mu_{2}$ \\ \hline $\boldsymbol{n}$ & 24 & 24 \\ \hline $\bar{x}$ & 0.79386 lb & 0.80841 lb \\ \hline $\mathbf{s}$ & 0.00441 lb & 0.00743 lb \\ \hline \end{tabular}
State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the Submit quiz 9:06 PM 11/24/2024

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Problem 587

- Hypothesis Tests for a Question 8, 10.3.33-P HW Score: $97.62 \%, 8.79$ of 9 points Part 6 of 9 Points: 0.79 of 1 Save
A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the College Board, scores are normally distributed with $\mu=518$ . The teacher obtains a random sample of 2200 students, puts them through the review class, and finds that the mean math score of the 2200 students is 523 with a standard deviation of 118 . Complete parts (a) through (d) below.
Click the icon to view the t-Distribution Area in the Right Tail. A. No, because every increase in score is practically significant. B. Yes, because the score became more than $0.97 \%$ greater. C. No, because the score became only $0.97 \%$ greater D. Yes, because every increase in score is practically significant. (d) Test the hypothesis at the $\alpha=0.10$ level of significance with $n=400$ students. Assume that the sample mean is still 523 and the sample standard deviation is still 118 . Is a sample mean of 523 significantly more than 518 ? Conduct a hypothesis test using the P-value approach.
Find the test statistic. $\mathrm{t}_{0}=$ $\square$ (Round to two decimal places as needed.) $v$ an example Get more help - Clear all Check answer 3 Nov 24 10:09 INTL 붕

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Problem 588

list
A cereal company claims that the mean weight of the cereal in its packets is less than 14 oz. Express the null hypothesis and the alternative hypothesis in symbolic form for a test to reject this claim. A. $\mathrm{H}_{0}: \mu<14$ $H_{1}: \mu \geq 14$ B. $H_{0}: \mu=14$ $H_{1}: \mu<14$ C. $H_{0}: \mu=14$ $H_{1}: \mu>14$ D. $H_{0}: \mu>14$ $H_{1}: \mu \leq 14$

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Problem 589

Provide an appropriate response.
A local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 10 new rackets at 41 psi. Suppose the two-tailed $P$ -value for the test described above (obtained from a computer printout) is 0.07 Give the proper conclusion for the test. Use alpha $=0.10$

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Problem 590

This test: 25 point(s) possible This question: 3 point(s) possible Submit test
A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal Complete parts (a) and (b) below. Use a 005 significance level for both parts \begin{tabular}{|c|c|c|} \hline & \multicolumn{2}{|c|}{ Proctored } \\ \hline $\mu$ & Nonproctored \\ \hline $\mu$ & $\mu_{1}$ & $\mu_{2}$ \\ \hline $n$ & 35 & 33 \\ \hline $x$ & 76.44 & 83.08 \\ \hline $s$ & 11.74 & 21.48 \\ \hline \end{tabular} D. Keject $\mathrm{H}_{0}$ . Ihere is sufticient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. $\square$ $\square$ $<\mu_{1}-\mu_{2}<$ (Round to two decimal places as needed.)

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Problem 591

Part 3 of 8 HW Score: $50 \%, 3$ of 6 points Points: 0 of 1 Save those who imme sample data B. The response variable is the number of students. The explanatory variab C. The response variable is the time to graduate. The explanatory variable is D. The response variable is the use of community college or not. The explar b) Explain why this study can be analyzed using inference of two sample means. A. The samples can be reasonably assumed to be random. B. The sample sizes are not more than $5 \%$ of the population. C. The population is given to be normally distributed. \begin{tabular}{|c|c|c|} \hline & Community College Transfer & No Transfer \\ \hline Sample mean time & 265 & 1164 \\ \hline to graduate, in years & 5.38 & 4.45 \\ \hline Sample standard deviation time to graduate, in years & 1.147 & 1.021 \\ \hline \end{tabular} D. The sample sizes are large (both greater than or equal to 30 ). $\qquad$ E. The samples are independent. Print Done c) Does the evidence suggest that community college transfer students take lo Determine the null and alternative hypotheses. B. $\mathrm{H}_{0}: \mu_{\text {community college }}>\mu_{\text {no transfer }}, \mathrm{H}_{1}: \mu_{\text {community college }}<\mu_{\text {no transfer }}$ C. $\mathrm{H}_{0}: \mu_{\text {community college }}=\mu_{\text {no transfer }}, \mathrm{H}_{1}: \mu_{\text {community college }}>\mu_{\text {no transfer }}$ D. $\mathrm{H}_{0}: \mu_{\text {community college }}=\mu_{\text {no transfer }}, \mathrm{H}_{1}: \mu_{\text {community college }}<\mu_{\text {no transfer }}$

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Problem 592

Part 1 of 4 HW Score: $66.9 \%, 6.69$ of 10 points Points: 0 of 1 Save
A professor at a local university designed an experiment to see if someone could identify the color of a candy based on taste alone. Students were blindfolded and then given a red-colored or yellow-colored candy to chew. (Half the students were assigned to receive the red candy and half to receive the yellow candy. The students could not see what color candy they were given.) After chewing, the students were asked to guess the color of the candy based on the flavor. Of the 110 students who participated in the study, 93 correctly identified the color of the candy. The results are shown in the accompanying technology printout. Complete parts a through c below.
Click the icon to view the technology printout. a. If there is no relationship between color and candy flavor, what proportion of the population of students would correctly identify the color?
The proportion would be $\square$ (Type an integer or a decimal.)
Technology Printdyst \begin{tabular}{|c|c|c|c|c|c|c|} \hline \multirow{4}{*}{ID_Color} & & Category & N & Observed Prop. & Test Prop & \begin{tabular}{l} Exact \\ Sig (2-tailed) \end{tabular} \\ \hline & Group 1 & Yes & 93 & 0.85 & 0.50 & 0.000 \\ \hline & Group 2 & No & 17 & 0.15 & & \\ \hline & Total & & 110 & 1 & & \\ \hline \end{tabular} Print Done Get more help -

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Problem 593

Points: 0 of 1 save
Customers who participate in a store's free loyalty card program save money on their purchases, but allow the store to keep track of the customer's shopping habits and potentially sell these data to third parties. A survey revealed that 221 of a random sample of 250 adults in a certain country would agree to participate in a store loyalty card program, despite the potential for information sharing. Let p represent the true proportion of all customers who would participate in a store loyalty card program. Complete parts a through g below. a. Compute a point estimate of $p$ .
The estimate is $\square$ . (Type an integer or a decimal. Do not round.)

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Problem 594

Out of 100 adults sampled, 85 had kids. Based on this, calculate a 95\% confidence interval for the percentage of all adults with kids. Use technology (such as a TI calculator) to assist in finding the answer. Give percentages rounded to one decimal place, and type the answer in interval notation. The $95 \%$ confidence interval for the percentage of adults who have children is....(Do not enter a \% sign.) $\square$ Add Work

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Problem 595

A certain region would like to estimate the proportion of voters who intend to participate in upcoming elections. A pilot sample of 50 voters found that 42 of them intended to vote in the election. Determine the additional number of voters that need to be sampled to construct a $97 \%$ interval with a margin of error equal to 0.07 to estimate the proportion.
The region should sample $\square$ additional voters. (Round up to the nearest integer.)

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Problem 596

\begin{tabular}{|l|l|l|} \hline First Question: & Grade & $\mathbf{3 0}$ \\ \hline \end{tabular}
The manager of a pizza- delivery company wants to advertise how fast they can deliver an order to a customer. From her records, she selects 12 delivery distance, 2, 5, 8, and 15 Km , with three deliveries at each distance. She records, for each delivery, the time (in minutes) it takes to carry the pizza from the company store to the customer. The resulting data are shown in table: \begin{tabular}{|l|c|c|c|c|c|c|c|c|c|c|c|c|} \hline Distance & 2 & 2 & 2 & 5 & 5 & 5 & 10 & 10 & 10 & 15 & 15 & 15 \\ \hline Time & 10.2 & 14.6 & 18.2 & 20.1 & 22.4 & 30.6 & 30.8 & 35.4 & 50.6 & 60.1 & 68.4 & 72.1 \\ \hline \end{tabular} (1) Find the Least Square Regression Line for this relationship? (2) How long do you expect it to take for this company to deliver a pizza to an address that is exactly 8 km from the store? (3) What is the best estimate of the variance? (4) Find the standard deviation of the point estimates of $\hat{\beta}_{0}$ ? (5) Find the standard deviation of the point estimates of $\hat{\beta}_{1}$ ? (6) Test $H_{0}: \beta_{1}=0 \quad$ vs $H_{1}: \beta_{1}>0$ , at $\alpha=0.05$ ? (7) Test $H_{0}: \beta_{0}=0 \quad$ vs $H_{1}: \beta_{0} \neq 0$ , at $\alpha=0.05$ ? (8) Calculate the coefficient of correlation between these two variables? (9)Test $H_{0}: \rho=0 \quad$ vs $H_{1}: \rho \neq 0$ , at $\alpha=0.05$ ?

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Problem 597

13. Tipping at a buffet Do customers who stay longer at buffets give larger tips? Charlotte, a statistics student who worked at an Asian buffet, decided to investigate this question for her second-semester project. While working as a hostess, she obtained a random sample of receipts, which included the length of time (in minutes) the party was in the restaurant and the amount of the tip (in dollars). Here is a scatterplot of these data. ${ }^{27}$ (a) Interpret the value $r=0.36$ . (b) Does increasing the amount of time spent in the restaurant cause an increase in the amount of the tip? Explain.

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Problem 598

13. A company that manufactures toothpaste is studying five different package designs. Assuming that one design is just as likely to be selected by a consumer as any other design, what selection probability would you assign to each of the package designs? In an actual experiment, 100 consumers were asked to pick the design they preferred. The following data were obtained. Do the data confirm the belief that one design is just as likely to be selected as another? Explain. \begin{tabular}{cc} Design & \begin{tabular}{c} Number of \\ Times Preferred \end{tabular} \\ 1 & 5 \\ 2 & 15 \\ 3 & 30 \\ 4 & 40 \\ 5 & 10 \end{tabular}

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Problem 599

$\checkmark 1$ 2 3 4 5 6 7 8 9 10 11 12
A pollster is going to sample a number of voters in a large city and construct a $90 \%$ confidence interval for the proportion who support the incumbent candidate for mayor. Find a sample size so that the margin of error will be no larger than 0.05 . Be sure to round up to the next whole number.
The required sample size is $\square$ .

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Problem 600

For problems 1 to 4, state the most likely hypothesis and compute both a Pearson correlation coefficient and a Spearman correlation coefficient. For problems 1 and 2, perform the computations for all problems both by hand and using SPSS. For problems 3 and 4, use SPSS only. In each case, consider which test, Pearson or Spearman, is the more appropriate choice.
1. An HMO administrator wants to examine the relationship of self-rated health to the number of physician visits made in 1 year. The self-rated health is rated on a scale of 1 to 5 , where $1=$ poor health and $5=$ excellent health; the number of physician visits made in the past year is shown in the table below:
Patient ID Self-Rated Health No. of Physician Visits in the Past Year \begin{tabular}{lll} \hline & the Past Year \\ \hline 1 & 5 & 2 \\ \hline 3 & 4 & 1 \\ \hline 4 & 4 & 2 \\ \hline 5 & 5 & 3 \\ \hline 6 & 4 & 3 \\ \hline 7 & 3 & 4 \\ \hline 8 & 3 & 4 \\ \hline 9 & 4 & 4 \\ \hline 10 & 2 & 5 \\ \hline 11 & 2 & 5 \\ \hline 12 & 3 & 5 \\ \hline \end{tabular}

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1 ...3 4 5 6 7 8 9 ...14

Statistical Inference

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The ppp-value for a hypothesis test turns out to be 0.051785. At a 7\% level of significance, what is the proper decision? Fail to reject H0H_{0}H0​ Reject H0H_{0}H0​

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57 Replies, 57. UnreadDiscussion: Hypothesis Testing: One Sample Instruction: Post your response first and then reply to two of your colleagues' posts. - Explain the difference between the z-test for mean using a P-Value and the z-test for mean using the rejection region(s).

Problem 520

Explain the conditions that are necessary to use the ttt-test to test the difference between two population means.

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Find the confidence interval for the true mean SAT score given a mean of 482 and a margin of error of 15.

Problem 532

Which of these is a statistical question? A. Lunch period length? B. Oldest student age? C. Classrooms count? D. Ages of classmates?

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In a sample of 290 adults, 261 had children. Construct a 95%95 \%95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places <p<<p<<p<

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Problem 573

The $p$ -value for a hypothesis test turns out to be 0.051785. At a 7\% level of significance, what is the proper decision? Fail to reject $H_{0}$ Reject $H_{0}$

57 Replies, 57. Unread
Discussion: Hypothesis Testing: One Sample Instruction: Post your response first and then reply to two of your colleagues' posts. - Explain the difference between the z-test for mean using a P-Value and the z-test for mean using the rejection region(s).

Explain the conditions that are necessary to use the $t$ -test to test the difference between two population means.

In a sample of 290 adults, 261 had children. Construct a $95 \%$ confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places $<p<$